(4y-3)(2y²+3y-5)
First , let's start with "4y"
4y*2y² = 8y³
4y*3y = 12y²
4y*-5 = -20y
Next, let's multiply by "-3"
-3*2y² = -6y²
-3*3y = -9y
-3*-5 = 15
Now, let's combine all of our values.
8y³+12y²-6y²-20y-9y+15 = 8y³+6y²-29y+15
Answer:
B (-3)
Step-by-step explanation:
The question did not spesify the stating value for n.
Assuming, n = 0 is the starting value.
1st term is when n = 0:
f(0) = (0)^2 - 5 = 0 - 5 = -5
2nd term: f(1) = (1)^2 - 5 = 1 - 5 = -4
3rd term: f(2) = (2)^2 - 5 = 4 - 5 = -1
4th term: f(3) = (3)^2 - 5 = 9 - 5 = 4
Therefore, the first 4 terms are: -5, -4, -1, 4.
Answer: Im not too good at math but I will try to help and I will say 70 is the answer...?
Im really sorry if I get this wrong
