well, -12+7 is 5 times (23-7=16) so that answer is 80 and 6-(-5*4=-20) so that is also 16
Answer:
The mean and the standard deviation of the sampling distribution of the number of students who preferred to get out early are 0.533 and 0.82
Step-by-step explanation:
According to the given data we have the following:
Total sample of students= 150
80 students preferred to get out 10 minutes early
Therefore, the mean of the sampling distribution of the number of students who preferred to get out early is = 80/150 = 0.533
Therefore, standard deviation of the sampling distribution of the number of students who preferred to get out early= phat - p0/sqrt(p0(1-p)/)
= 0.533-0.5/sqrt(0.5*0.5/15))
= 0.816 = 0.82
Answer: 720.3
Step-by-step explanation:
First you divide 6.4 by 9.8 then you divide by 470.40 to get 720.3
Hope this helps
Answer:
2 21/13
Step-by-step explanation:
