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2 years ago

5

Four students took an exam the fraction of the total possible points that each received is given which students had the highest

score. If students receive a whole number of points on every exam item can the exam be worth 80 points

1 answer:

Fittoniya [83]2 years ago

7 0

Answer:

4% out of 100

Step-by-step explanation:

4% out of 100 students took the exam

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Y-4=0 in standard form

wolverine [178]

Standard form : Ax + By = C

y - 4 = 0
y = 4...this is a horizontal line and a horizontal line has a 0 slope

so in standard form, ur equation is : 0x + y = 4

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2 years ago

Points J and K are midpoints of the sides of triangle FGH. What is the value of y?

sashaice [31]

The answer

the complement of the question is

What is the value of y?

2
5
7
<span>8
</span>
According to the image, HKJ and FGH are similar, we can apply the theorem of thales
since GK and GF are parallels, so

HK / HF = HJ / HG = KJ / GF and as we see on the figure, HK = HF /2, this implies 2HK =HF

HK / 2HK = KJ / GF it is equivalent to 1/2 = 2y+5 / 5y +3

likewise, equivalent to 5y +3 = 4y +10, 5y-4y = 10-3, and y = 7

so the answer is 7

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3 years ago

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Write a linear function that relates y to x <br><br> y=

son4ous [18]

y=x-2

hope this helped :)

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2 years ago

What is the area of the trapezoid? The diagram is not drawn to scale.

Katyanochek1 [597]

Answer:

The area of trapezoid is 72 cm²

Step-by-step explanation:

Given : A trapezoid with given dimensions.

We have to find the area of trapezoid ABCD.

Consider the given trapezoid ABCD ,

AB = EF = 8 cm

and CE = FD = 4 cm

Then CD = CE + EF + FD = 4 + 8 + 4 = 16 cm

Thus, Area of trapezoid = $\frac{1}{2}\cdot \text{(Sum of parallel sides)} \cdot height$

here, height = 6 cm

and sum of parallel sides = AB + CD = 16 + 8 = 24 cm

Thus, Area of trapezoid = $\frac{1}{2}\cdot 24 \cdot 6$

Simplify, we have,

Area of trapezoid = 72 cm²

Thus, The area of trapezoid is 72 cm²

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2 years ago

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1. tan a = cot(a + 10°)

Temka [501]

Answer:

$a=40+90n$

Step-by-step explanation:

Use a cofunction identity on the right hand side or left hand side...

So $\tan(a)=\cot(90-a)$ .

We have the equation:

$\tan(a)=\cot(a+10)$

Make the above replacement:

$\cot(90-a)=\cot(a+10)$

Since cotangent has period 180 degrees, we can also write this as:

$\cot(90-a+180n)=\cot(a+10)$

So solving the following will give us a set of solutions for $a$ :

$90-a+180n=a+10$

Add $a$ on both sides:

$90+180n=2a+10$

Subtract 10 on both sides:

$80+180n=2a$

Divide both sides by 2:

$40+90n=a$

Symmetric property:

$a=40+90n$

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2 years ago