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lutik1710 [3]
2 years ago
11

Need helpppp helppp plzzzz 20 points

Mathematics
2 answers:
Westkost [7]2 years ago
6 0

Answer: 7^3/7^6= 1/343

Step-by-step explanation: We move 7^-6 to a denominator because we cannot have a negative exponent in the numerator.

So it would be 7^3/7^6

Which then would be 7*7*7/7*7*7*7*7*7

Which would equal 343/117649

Simplify and you get 1/343

HACTEHA [7]2 years ago
4 0
It’s 69 bc add 1 to 19
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Several ways, take the diameter and divide it by half.

Take the circumference "C" and r = C/2π

Step-by-step explanation:

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2 years ago
EXPLAIN why we placed the value of x= 4/3( the minimum value) into the equ of gradient(dy/dx) [in the answer, marking scheme att
aliina [53]
y=x(x-2)^2
\implies y'=(x-2)^2+2x(x-2)=3x^2-8x+4=(3x-2)(x-2)=0
\implies x=\dfrac23,x=2

are the critical points, and judging by the picture alone, you must have b=\dfrac23 and a=2. (You might want to verify with the derivative test in case that's expected.)

Then the shaded region has area

\displaystyle\int_0^2x(x-2)^2\,\mathrm dx=\dfrac43

I'll leave the details to you.

Now, for part (iv), you're asked to find the minimum of \dfrac{\mathrm dy}{\mathrm dx}=y', which entails first finding the second derivative:

y'=3x^2-8x+4
\implies y''=6x-8

setting equal to 0 and finding the critical point:

6x-8=0\implies x=\dfrac86=\dfrac43

This is to say the minimum value of \dfrac{\mathrm dy}{\mathrm dx} *occurs when x=\dfrac43*, but this is not necessarily the same as saying that \dfrac43 is the actual minimum value.

The minimum value of \dfrac{\mathrm dy}{\mathrm dx} is obtained by evaluating the derivative at this critical point:

m=\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=4/3}=3\left(\dfrac43\right)^2-8\left(\dfrac43\right)+4=-\dfrac43
4 0
3 years ago
Identify the meaning of the variables in the point-slope form of a line.
hjlf

Answer:

(x,y) = Any point on the line

m = the slope of the line

(x₁, y₁) = A given point on the line

Step-by-step explanation:

the equation of a straight line is;

y = mx + c

where;

x and y are any point on the line

m is the slope of the line

c is the intercept on the y axis

And a given point on (x,y) can be written as (x₁, y₁)

Therefore, for the case above;

(x,y) = Any point on the line

m = the slope of the line

(x₁, y₁) = A given point on the line

3 0
3 years ago
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