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2 years ago

What's the solution to the inequality????? 20 points

Mathematics

2 answers:

katrin2010 [14]2 years ago

6 0

Answer:

the answer is A

Step-by-step explanation:

The answer is A

vovangra [49]2 years ago

5 0

Answer:

x<229.7

Step-by-step explanation:

4.7>x-225

x<4.7+225

x<229.7

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Can someone write a sonnet about dogs for me?

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Answer:

lol

Step-by-step explanation:

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2 years ago

A card is drawn randomly from a standard 52-card deck. Find the probability of the given event. (a) The card drawn is 5. The pro

Dmitrij [34]

Answer:

a. 1 / 13
b. 3 / 13
c. 10 / 13

Step-by-step explanation:

There are four 5's in the deck. This means that, from 52 possible cards to drawn, we have 4 chances of drawing a 5. This means that the probability will be:

$p = \frac{4}{52}$

$p = \frac{1}{13}$

For every suit, there are three face cards, J, Q and K. There are 4 suits, so, the total number of face cards its:

$4 * 3 = 12$

The total possible cards are, still, 52, so, the probability will be

$p = \frac{12}{52}$

$p = \frac{3}{13}$

We know that the card drawn must be a face card, o not being a face card. There is no third choice here. So, the probability of drawing a face card OR not drawing a face car its:

$p = \frac{52}{52} = 1$

$p(the \ card \ is \ a \ face \ card) + p(the \ card \ is \ not \ a \ face \ card) = 1$

$p(the \ card \ is \ not \ a \ face \ card) = 1 - p(the \ card \ is \ a \ face \ card)$

but, we know that

$p(the \ card \ is \ a \ face \ card = \frac{3}{13}$

$p(the \ card \ is \ not \ a \ face \ card) = 1 - \frac{3}{13}$

$p(the \ card \ is \ not \ a \ face \ card) = \frac{10}{13}$

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2 years ago

A radio antenna is kept perpendicular to the ground by three wires of equal length. The wires touch the ground at three points o

Elena-2011 [213]

Answer:

The coordinates of the base of the antenna is (-6. 1)

Step-by-step explanation:

Here we are required to find the center of a circle given points on the circumference

The equation of a circle is

(x - h)² + (y - k)² = r²

Where:

x and y are points on the circumference

h and k are coordinates of the center of the circle and

r = The radius of the circle

Since we have the values for the points on the circumference, we are left with three unknowns, which we can find with three equations as follows;

By plugging in the values for x and y at the respective points we get,

At (9, -19) → (9 - h)² + (-19 - k)² = r²...............(1)

At (-21, -19) → (-21 - h)² + (-19 - k)² = r².....,...(2)

At (14, 16 ) → (14 - h)² + (16 - k)² = r² ............(3)

Solving, we get from (1) (-19 - k)² = r² - (9 - h)²

Plugging in the value of (-19 - k)² in equation (2) we get

(-21 - h)² + r² - (9 - h)² = r²

So that (-21 - h)² - (9 - h)² = r² - r² = 0

and (-21 - h)² - (9 - h)² = 0 gives

60·h +360 = 0 or h = -6

Plugging in the value of h = -6 in equation (3) we get

(14 - (-6))² + (16 - k)² = r²

20² + (16 - k)² = r² .................(4)

similarly from equation (1) we get

(9 - (-6))² + (-19 - k)² = r²

15² + (-19 - k)² = r² ................(5)

Subtracting equation (5) from (4) gives

20² - 15² + (16 - k)² - (-19 - k)² = 0

Which gives

-70·k + 70 = 0

or k = 1

Therefore the coordinates of the base of the antenna = (-6. 1).

6 0

3 years ago