I believe notation one would be 8:9 and notation two would be 8 to 9
Answer:
Below
Step-by-step explanation:
Substituting the given values:
f(6) = 6(2/3) - 2 = cube root of 6^2 - 2 = cube root 36 - 2
f(-6)= (-6)(2/3) - 2 = cube root of(-6)^2 - 2 = cube root 36 - 2
So This is true,
f(6) = cube root of 6^2 - 2 = cube root 36 - 2 = 1.3019
2 * f(3) = 2 * (cube root of 3^2 - 2 ) = 2 * (cube root of 9 - 2) = 0.1602
So False,
Answer:
<h2>
<em><u>2</u></em><em><u>x</u></em></h2>
Step-by-step explanation:
<h2>
<em><u>6</u></em><em><u>x/</u></em><em><u>3</u></em><em><u>=</u></em><em><u>2</u></em><em><u>x</u></em></h2>
<em><u>thank</u></em><em><u> you</u></em>
<em><u>that's</u></em><em><u> all</u></em>
Answer:
y =5
Step-by-step explanation:
m=
−9−7
5−5
=
−16
0
=0
y=mx+b
5=(0)(7)+b
b=5
therefore y = 5
Answer:
1) It is geometric
a) In each trial you can obtain 11 or obtain something else (and fail)
b) Throw 2 dices and watch if the result is 11 or not
c) The probability of success is 1/18
2) It is not geometric, but binomal.
Step-by-step explanation:
1) This is effectively geometric. When you see the sum of 2 dices, you can separate the result in two different outcomes: when the sum is 11 and when the sum is different from 11.
A trial is constituted bu throwing 2 dices and watching if the sum of the dices is 11 or not.
In order to get 11 you need one 5 in one dice and 1 six in another. As a consecuence, you have 2 favourable outcomes (a 5 in the first dice and a 6 in the second one or the other way around). The total amount of outcomes is 6² = 36, and all of them have equal probability. This means that the probability of success is 2/36 = 1/18.
2) This is not geometric distribution. The geometric distribution meassures how many tries do you need for one success. The amount of success in 10 trias follows a binomial distribution.
