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forsale [732]
3 years ago
14

There are 3.2 million teachers in the United States and 5.66 x 107 students. How many times more students than

Mathematics
1 answer:
Marat540 [252]3 years ago
3 0

Answer:

602.42 million

Step-by-step explanation:

I know the answer is 602.42 million because I used addition and subtraction.

First, I knew there was 5.66x 107 million students. So, I multiplied 5.66 and 107, and I got 605.62 million. I knew there were 3.2 million teachers in the US. Next, I subtracted 3.2 million from 605.62 million.

605.62-3.2=602.42

So, there are 602.42 million more students than teachers in the United States.

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Suppose you have $60 to buy shrimp and chicken wings for a party. Shrimp costs $10/Ib and wings cost $6/Ib.
noname [10]

Answer:

you can buy 5lb of wings for $30 and 3lb of shrimp for $30 too

Step-by-step explanation:I forgot what a linear equation was sorry :/

5 0
3 years ago
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I’m tired and I need to explain this. But I don’t feel like writing it
alina1380 [7]

Answer:

area of the figure A is 7.5m^2

Step-by-step explanation:

figure A is the combination of rectangle and triangle.

so

area of figure A = area of triangle + area of rectangle

= 1/2 X b X h + L X b

= 1/2 X 1 X (1+1+1) + (1+1+1) X (1+1)

= 0.5 X 1 X 3 + 3 X 2

= 1.5 + 6

= 7.5 m^2

8 0
2 years ago
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Looking at the top of tower A and base of tower B from points C and D, we find that ∠ACD = 60°, ∠ADC = 75° and ∠ADB = 30°. Let t
katrin2010 [14]

Answer:

\text{Exact: }AB=25\sqrt{6},\\\text{Rounded: }AB\approx 61.24

Step-by-step explanation:

We can use the Law of Sines to find segment AD, which happens to be a leg of \triangle ACD and the hypotenuse of \triangle ADB.

The Law of Sines states that the ratio of any angle of a triangle and its opposite side is maintained through the triangle:

\frac{a}{\sin \alpha}=\frac{b}{\sin \beta}=\frac{c}{\sin \gamma}

Since we're given the length of CD, we want to find the measure of the angle opposite to CD, which is \angle CAD. The sum of the interior angles in a triangle is equal to 180 degrees. Thus, we have:

\angle CAD+\angle ACD+\angle CDA=180^{\circ},\\\angle CAD+60^{\circ}+75^{\circ}=180^{\circ},\\\angle CAD=180^{\circ}-75^{\circ}-60^{\circ},\\\angle CAD=45^{\circ}

Now use this value in the Law of Sines to find AD:

\frac{AD}{\sin 60^{\circ}}=\frac{100}{\sin 45^{\circ}},\\\\AD=\sin 60^{\circ}\cdot \frac{100}{\sin 45^{\circ}}

Recall that \sin 45^{\circ}=\frac{\sqrt{2}}{2} and \sin 60^{\circ}=\frac{\sqrt{3}}{2}:

AD=\frac{\frac{\sqrt{3}}{2}\cdot 100}{\frac{\sqrt{2}}{2}},\\\\AD=\frac{50\sqrt{3}}{\frac{\sqrt{2}}{2}},\\\\AD=50\sqrt{3}\cdot \frac{2}{\sqrt{2}},\\\\AD=\frac{100\sqrt{3}}{\sqrt{2}}\cdot\frac{ \sqrt{2}}{\sqrt{2}}=\frac{100\sqrt{6}}{2}={50\sqrt{6}}

Now that we have the length of AD, we can find the length of AB. The right triangle \triangle ADB is a 30-60-90 triangle. In all 30-60-90 triangles, the side lengths are in the ratio x:x\sqrt{3}:2x, where x is the side opposite to the 30 degree angle and 2x is the length of the hypotenuse.

Since AD is the hypotenuse, it must represent 2x in this ratio and since AB is the side opposite to the 30 degree angle, it must represent x in this ratio (Derive from basic trig for a right triangle and \sin 30^{\circ}=\frac{1}{2}).

Therefore, AB must be exactly half of AD:

AB=\frac{1}{2}AD,\\AB=\frac{1}{2}\cdot 50\sqrt{6},\\AB=\frac{50\sqrt{6}}{2}=\boxed{25\sqrt{6}}\approx 61.24

3 0
2 years ago
Read 2 more answers
Factor 4x 2 + 12x + 5 . (2x + 5)(2x + 1)
Juliette [100K]
Factor
in form
ax²+bx+c form
use the ac method
1. mulitply a and c
2. factor the result such that the 2 factors add to b
3. split b into those 2 factors
4. group the terms
5. undistribute common factors
6. undistribute again





first multiply ac
4 times 5=20
now
what 2 numbers multiply to 20 and add to 12
2 and 10
4x²+2x+10x+5
group
(4x²+2x)+(10x+5)
undistribute
2x(2x+1)+5(2x+1)
undistribute the (2x+1)
(2x+1)(2x+5) is factored form whih you have there, nice
8 0
3 years ago
World war 1 lasted from August 4th 1914 until November 11th, 1918. During this time an estimated 10 million lives were lost. Abo
Kryger [21]
The question is so dry, mechanical, and devoid of emotion
that it's terrifying.

There is no way to assign a number to "How many people were
dying per day", and I would prefer not even to think about it in
those terms.

-- The period of time from August 4, 1914 until November 11, 1918 is 1,560 days.

-- The "average", or better, the "unit rate" of 10 million events in 1,560 days
is the quotient

                   (10,000,000 events) / (1,560 days) 

               =  6,410.3 events per day

               =     267.1 events per hour

               =       4.45 events per minute.


Reciprocally, this is a unit rate of 

                  13.48 seconds per event,
                  sustained continuously for 4.274 years !

When will we ever learn ! ?
6 0
3 years ago
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