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3 years ago

Ill give you 22 brainly if you answer this

Mathematics

1 answer:

skelet666 [1.2K]3 years ago

8 0

Answer:

One thing that they have in common is that point A is on the same axis. Something different is that the second version is only half the size of the original.

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Find the average rate of change of f(x)=2x-1 from x=-1 to x=2

MrMuchimi

The average rate of change from x = -1 to x = 2 is 2

Solution:

Given function is:

f(x) = 2x - 1

We have to find the average rate of change from x = -1 to x = 2

The average rate of change is given as:

$\text {Average rate of change}=\frac{f(b)-f(a)}{b-a}$

The average rate of change from x = -1 to x = 2 is given by formula:

$\text {Average rate of change}=\frac{f(2)-f(-1)}{2-(-1)}\\\\\text {Average rate of change}=\frac{f(2)-f(-1)}{3}$

Find f(2) and f( - 1)

Substitute x = 2 in given function

f(2) = 2(2) - 1 = 4 - 1 = 3

Substitute x = -1 in given function

f( - 1) = 2(-1) - 1 = -2 - 1 = -3

Substitute the values in above formula,

$\text {Average rate of change}=\frac{3-(-3)}{3}=\frac{6}{3}=2$

Thus average rate of change from x = -1 to x = 2 is 2

3 0

3 years ago

3.Find the area of Triangle and Parallelogram having base 13.5cm and height is 18cm.

patriot [66]

Base=13.5cm
Height=18cm

$\\ \sf\longmapsto Area=\dfrac{1}{2}Base\times Height$

$\\ \sf\longmapsto Area=\dfrac{1}{2}(18)(13.5)$

$\\ \sf\longmapsto Area=9(13.5)$

$\\ \sf\longmapsto Area=121.5cm^2$

3 0

2 years ago

Seventy-two percent of the light aircraft that disappear while in flight in a certain country are subsequently discovered. Of th

Anton [14]

Answer:

a) 0.105 = 10.5% probability that it will not be discovered if it has an emergency locator.

b) 0.522 = 52.2% probability that it will be discovered if it does not have an emergency locator.

c) 0.064 = 6.4% probability that 7 of them are discovered.

Step-by-step explanation:

For itens a and b, we use conditional probability.

For item c, we use the binomial distribution along with the conditional probability.

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

a) If it has an emergency locator, what is the probability that it will not be discovered?

Event A: Has an emergency locator

Event B: Not located.

Probability of having an emergency locator:

66% of 72%(Are discovered).

20% of 100 - 72 = 28%(not discovered). So

$P(A) = 0.66*0.72 + 0.2*0.28 = 0.5312$

Probability of having an emergency locator and not being discovered:

20% of 28%. So

$P(A cap B) = 0.2*0.28 = 0.056$

Probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.056}{0.5312} = 0.105$

0.105 = 10.5% probability that it will not be discovered if it has an emergency locator.

b) If it does not have an emergency locator, what is the probability that it will be discovered?

Probability of not having an emergency locator:

0.5312 of having. So

$P(A) = 1 - 0.5312 = 0.4688$

Probability of not having an emergency locator and being discovered:

34% of 72%. So

$P(A \cap B) = 0.34*0.72 = 0.2448$

Probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.2448}{0.4688} = 0.522$

0.522 = 52.2% probability that it will be discovered if it does not have an emergency locator.

c) If we consider 10 light aircraft that disappeared in flight with an emergency recorder, what is the probability that 7 of them are discovered?

p is the probability of being discovered with the emergency recorder:

0.5312 probability of having the emergency recorder.

Probability of having the emergency recorder and being located:

66% of 72%. So

$P(A \cap B) = 0.66*0.72 = 0.4752$

Probability of being discovered, given that it has the emergency recorder:

$p = P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.4752}{0.5312} = 0.8946$

This question asks for P(X = 7) when $n = 10$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 7) = C_{10,7}.(0.8946)^{7}.(0.1054)^{3} = 0.064$

0.064 = 6.4% probability that 7 of them are discovered.

8 0

3 years ago

(7x+3) (10x-14) HELP PLEASE

liubo4ka [24]

Answer:

70 $x^{2}$ +30x-140

Step-by-step explanation:

(7x+3) (10x-14)

70 $x^{2}$ -98+30x-42

70 $x^{2}$ +30x-42-98

70 $x^{2}$ +30x-140

7 0

3 years ago

Read 2 more answers

Please help me..asap

Ivenika [448]

Answer:

the first one obviously isnt random
the second one is selective then random
the third one is also selective
the fourth one is random

6 0

2 years ago