Based on the given parameters, the value of x in the rectangle is 6
<h3>How to determine the value of x in the rectangle?</h3>
The given parameters are
Perimeter = 62
From the figure, we have
Length = 2x
Width = x + 13
The perimeter is calculated as:
P =2 * (L + W)
This gives
2 * (2x + x + 13) = 62
So, we have
2 * (3x + 13) = 62
Divide both sides in the above equation by 2
3x + 13 = 31
Subtract both sides in the above equation by 13
3x = 18
Divide both sides in the above equation by 3
x = 6
Hence, the value of x in the rectangle is 6
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Answer:
Assuming (6 9) is a fraction I just multipled the coordinates of A,B,C,D by that
Step-by-step explanation:
Example: A coordinates are (-5,-2) so I multiplied -5 by 6/9 which is -10/3, and -2 by 6/9 which is -4/3.
I then plotted (-10/3,-4/3), which would be A'
Do the same for the rest of BCD to find B'C'D'
Answer:
Step-by-step explanation:
imagine 38 n = lets say b
so b/b/b/b/b
and divide that by 38
Since , the relation is linear .
Let equation is y = mx + c .
Putting , x = 0 and y = 32 .
32 = c .......( 1 )
Also , putting x = 100 and y = 212 .
We get :
212 = 100m + c .......( 2 )
Comparing equation 1 and 2 .
100m = 212 - 32
x = 1.8
Therefore , y = 1.8x + 32 .
Hence , this is the required solution .
