For the answer to the question above, a system of equations has no solution when the lines representing the equation are parallel but do not coincide. For two lines to be parallel, the must have the same gradient i.e. coefficient of x when y is made the subject of formula must be equal.
If one of the equations is
y = 8x + 7,
then the other equation will be
y = 8x - 7
The answer is 450ml so hope this helps all of you who had this problem
Answer:
Well, that is simple. You first must find the slope of the line from the 2 given points by using the slope formula. Which is y2-y1/x2-x1. So 2-4/-2-2 which equals -2/-4 which is 1/2. So the slope is 1/2. Now we can use the slope intercept form which is y=mx+b to find the slope equation. So we plug in one the points, say (2,4) and get y=1/2x+3. So now we plug in (6,y) Since we know x we can find y. y=1/2(6)+3 which gives us y=6. So y is 6.
y = mx + b
-3 = -2(-5) + b
-3 = 10 + b
-13 = b
y = -2m - 13
The line would pass through -13 on the y-axis and it would go down 2 and move to the right 1 for every new point.
Hope this helps! ;)
