2 years ago

What is the area of this composite figure?

Mathematics

1 answer:

MakcuM [25]2 years ago

7 0

Answer:

249cm or the third option

Step-by-step explanation:

I got it right on the test. Good luck to you!

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boyakko [2]

Should be 7 if not then sorry

3 0

2 years ago

RS bisects TU at Q. If TQ=5k-9 and QU=15-x

snow_lady [41]

Answer:

x = 4, TU = 22

Step-by-step explanation:

Given that TS bisects TU at Q , then

TQ = QU , substitute values

5x - 9 = 15 - x ( add x to both sides )

6x - 9 = 15 ( add 9 to both sides )

6x = 24 ( divide both sides by 6 )

x = 4

Thus

TU = 5x - 9 + 15 - x = 4x + 6 = 4(4) + 6 = 16 + 6 = 22

4 0

3 years ago

-8x+2(4x+2)=4 what does x equal

Bess [88]

Answer:

x=0

Step-by-step explanation:

-8x + 2(4x + 2) = 4

Use distributive property to get rid of the parentheses

-8x + 8x + 4 = 4

Add the like terms.

x + 4 = 4

Subtract both sides by four.

x = 0

7 0

3 years ago

The lengths of the two diagonals of a rhombus are 6 cm and 8 cm. Find the length of its perimeter (in

adelina 88 [10]

Answer:

<em>The perimeter of the rhombus is 20 cm</em>

Step-by-step explanation:

<u>Perimeter of a Rhombus</u>

Given the lengths of the two diagonals of a rhombus, let's call them a and b, the perimeter of the rhombus is given by:

$P=2\sqrt{a^2+b^2}$

The values of the diagonals provided by the question are a=6 cm, b=8 cm, thus the perimeter is:

$P=2\sqrt{6^2+8^2}$

$P=2\sqrt{36+64}$

$P=2\sqrt{100}=2*10$

$P=20\ cm$

The perimeter of the rhombus is 20 cm

3 0

2 years ago

If f(x) and f^-1(x) are inverse functions of each other and f(x) = 2x+5, what is f^-1(8) ? O -1 O 3/2 O 41/8 O 23

Nookie1986 [14]

Answer:

Step-by-step explanation:

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2 years ago