Answer:
<h3>The answer is 16.67 m/s²</h3>
Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula

f is the force
m is the mass
From the question we have

We have the final answer as
<h3>16.67 m/s²</h3>
Hope this helps you
The velocity (V) of a wave is the frequency (F) times the wave length (lambda):
V = F * lamda
lambda is the distance from crest to crest which is twice the distance from crest to trough.
=> lamba = 2 * 3.00 m = 6.00 m
F = number of waves / time = 13.0 waves / 20.2 s
Now you can plug in the values in the formula of V:
V = 6.00 m/wave* 13.0 waves / 20.2 s = 3.86 m/s
Answer: 3.86 m/s
The answer is elliptical orbits. Here is are my reason for thinking it is what I know it is. All planets move in elliptical orbits, with the sun at one focus. This is one of Kepler's laws. The elliptical shape of the orbit is a result of the inverse square force of gravity. The eccentricity of the ellipse is greatly exaggerated here.
Answer:
The velocity of motion at which the occupants of the car appear to weigh 20% less than their normal weight is approximately 19.81 m/s
Explanation:
The given parameters are;
The curvature of the hill, r = 200 m
Due to the velocity, v, the occupants weight = 20% less than the normal weight
The outward force of an object due to centripetal (motion) force is given by the following equation;

Where;
r = The radius of curvature of the hill = 200 m
Given that the weight of the occupants, W = m × g, we have;


v = √(0.2 × g × r)
By substitution, we have;
v = √(0.2 × 9.81 × 200) ≈ 19.81
The velocity of motion at which the occupants of the car appear to weigh 20% less than their normal weight ≈ 19.81 m/s.