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USPshnik [31]
3 years ago
13

Help please!! Physics grade 8​

Physics
1 answer:
Phoenix [80]3 years ago
8 0

Answer:

im only in 7th..

Explanation:

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With a total force of 20,000 newtons, an airplane has a mass of 1,200 kg. What is its acceleration?
swat32

Answer:

<h3>The answer is 16.67 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

m =  \frac{20000}{1200}  =  \frac{200}{12}  \\  = 16.66666...

We have the final answer as

<h3>16.67 m/s²</h3>

Hope this helps you

8 0
3 years ago
Pepe and alfredo are resting on an offshore raft after a swim. they estimate that 3.00 m separates a trough and an adjacent cres
Orlov [11]
The velocity (V) of a wave is the frequency (F) times the wave length (lambda):

     V =  F * lamda

lambda is the distance from crest to crest which is twice the distance from crest to trough.

=> lamba = 2 * 3.00 m = 6.00 m

F = number of waves / time = 13.0 waves / 20.2 s

Now you can plug in the values in the formula of V:

V = 6.00 m/wave* 13.0 waves / 20.2 s = 3.86 m/s

Answer: 3.86 m/s
8 0
3 years ago
planets in our solar system do not revolve around the sun in perfect circles. their orbits are nore like ovals. which term do sc
luda_lava [24]

The answer is elliptical orbits. Here is are my reason for thinking it is what I know it is. All planets move in elliptical orbits, with the sun at one focus. This is one of Kepler's laws. The elliptical shape of the orbit is a result of the inverse square force of gravity. The eccentricity of the ellipse is greatly exaggerated here.

6 0
3 years ago
1. *A car is going over the top of a hill whose curvature approximates a circle of radius 200 m. At
Greeley [361]

Answer:

The velocity of motion at which the occupants of the car appear to weigh 20% less than their normal weight is approximately 19.81 m/s

Explanation:

The given parameters are;

The curvature of the hill, r = 200 m

Due to the velocity, v, the occupants weight = 20% less than the normal weight

The outward force of an object due to centripetal (motion) force is given by the following equation;

F_c = \dfrac{m \times v^2}{r}

Where;

r = The radius of curvature of the hill = 200 m

Given that the weight of the occupants, W = m × g, we have;

F_c = 0.2 \times W = 0.2 \times m \times g

\therefore 0.2 \times m \times g = \dfrac{m \times v^2}{r}

v = √(0.2 × g × r)

By substitution, we have;

v = √(0.2 × 9.81 × 200) ≈ 19.81

The velocity of motion at which the occupants of the car appear to weigh 20% less than their normal weight ≈ 19.81 m/s.

3 0
3 years ago
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