Meters per second, and the time is in minutes, so 14.2 times 60(how many seconds in 1 minute) is 852 seconds then velocity is meters divided by seconds, so 400 divided by 852 is 0.47 m/s rounded to the hundredths place
Answer:
none of the answers is correct, the time is the same t₁ = t₂ = 0.600 s
Explanation:
This is a kinematics exercise, analyze the situation a bit. The vertical speed in both cases is the same is zero, the horizontal speed in the second case is double (vₓ₂ = 2 vₓ₁)
let's find the time to hit the ground
y = y₀ + I go t - ½ g t²
0 = y₀ - ½ g t²
t = √ 2y₀ / g
with the data from the first launch
y₀i = ½ g t²
y₀ = ½ 9.8 0.6²
y₀ = 1,764 m
with this is the same height the time to descend in the second case is the same
t₂ = 0.600 s
this is because the horizontal velocity change changes the offset on the x axis, but does not affect the offset on the y axis
Therefore, none of the answers is correct, the time is the same
t₁ = t₂ = 0.600 s
Object B has the slowest moving molecule because yea<span />
Explanation:
Okay, well, Saturn's rings form a wide and complex system, consisting mostly of particles and pieces of ice, and are highly visible. They may have formed from one or more moons that broke up due to a collision, or are left over from early debris that never coalesced into a moon... And, The rings of Uranus are thin and hard to see, consisting mostly of chunks of carbon and hydrocarbons with very little reflectivity. They may also have formed from the breakup of a small moon due to a collision. They may be kept thin by the presence of shepherd moons.
Hope I helped !
:)
Answer:
J = 2.044x10⁶ A/m²
v = 1.50x10⁻⁴ m/s
Explanation:
The current density (J) of the copper wire is giving by:
<em>where I: electric current and A: cross-sectional area of the copper wire</em>
<u>The cross-sectional area of the copper wire can be calculated by:</u>
<u>Substituting the calculated area in the equation (1) we have:</u>
Hence, the current density is 2.044x10⁶ A/m².
To find the drift speed (v), we need to use the next equation:
<em>where n: the free-electron density, q: module of the charge of the electron </em>
So, the drift speed is 1.50x10⁻⁴ m/s.
Have a nice day!
