Ok let’s say he folds N=14 so F would be the other q4
Answer:
4 boxes bc they're 12 in a dozen
Answer:
6.552×10³×10
6.552×10^3+1
6.552×10^4 is the standard form
i hope this will help you :)
Set 2x=x²-3 to each other.
Subtract 2x from both sides and get the following
x²-3-2x
Rearranging the formula to make factoring easier, we get
x²-2x-3
Factor and you should get the following:
(x-3)(x+1)
set both equal to 0 and solve for x.
x-3=0⇒x=3
x+1=0⇒x=-1
Now plug both of these values back into one of your original equations to get your y-values. It does not matter which equation you plug your xs back into due to the fact they intersect at the same x, and thus will also intersect at the same y.
For times sake,
y=2x
plug in x=3 and get y=6
plug in x=-1 and get y=-2
Ergo, the equations y=2x and y=x²-3 intersect at
(3,6) and (-1,-2)
a. HCF of 48 and 72 is 24
He can use 24 plates maximum.
b. 48/24 = 2
72/24 = 3
He can put 2 carrot sticks and 3 cheese puffs on each plate.
Hope this helps