The denominator of any fraction cannot be equal to zero. This is because if the denominator is equal to zero, the, the fraction itself would be "undefined".
Applying this to the above mentioned problem, we will find two denominators including the term "x". These two denominators cannot be equal to zero.
First fraction:
1/x ..................> x cannot be equal to zero
Second fraction:
1/(x^2 - 3x -4) = 1/(x - 4)(x + 1)
The denomination will be equal to zero if x = 4 or x = -1
........> x cannot be equal to 4 or -1
Based on this, the restrictions on x are as follows:
x cannot be equal to 0,4 or -1
Answer:
Step-by-step explanation:
The formula for this, specific to our circle, is
∠RQP = 
(arc SP - arc RP) and filling in:
∠RQP = 
and
∠RQP = 
so
∠RQP = 42°
30 over 4 = 15·2 over 2·2 = 15 over 2 = 1 + 7·2 over 2 = 7 1 over 2
Whole number =7
Fraction = 1 over 2
Hope this helps
Eric has 46 total marbles (4*10)+6
Answer:x>7 or x ≤ -3
Solving the 1st inequality
-6x +14 < -28 --------------- (Collect like terms)
-6x < -28 - 14
-6x < - 42 -------------------- (Divide both sides by -6)
Note: If you decide an inequality expression by a negative value, the inequality sign changes)
-6x/-6 > -42/-6
x > 7
Solving the 2nd inequality
9x + 15 ≤ −12 ----------- (Collect like terms)
9x ≤ −12 - 15
9x ≤ −27 ------------------(Divide both sides by 9)
9
9x/9 ≤ −27/9
x ≤ -3
Bring both results together, we get
x>7 or x ≤ -3
The final result is complex (i.e. can't be combined together).
Step-by-step explanation:
