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Dmitry_Shevchenko [17]
3 years ago
9

Solve by factorising

middle" class="latex-formula">+16x+55=0
Mathematics
1 answer:
Paladinen [302]3 years ago
6 0

Step-by-step explanation:

\underline{ \underline{ \text{Solving \: a \: quadratic \: equation \: by \: factorisation \: method}}} :

In this method , the second order of polynomial ax² + bx + c is factorised and expressed as the product of two linear factors. Then each linear factor is separately solved to get the required solutions of the equation by applying zero factor property. In zero factor property , if p•q = 0 , then either p = 0 or q = 0 . In other words , if the product of two numbers is 0 , then one or both of the numbers must be 0.

\underline{ \underline{ \text{Let's \: solve}}} :

\tt{ {x}^{2}  + 16x +  55 = 0}

Here , we have to find the two numbers that multiplies to 55 and adds to 16.

⤑ \tt{ {x}^{2}  + (11 + 5)x + 55 = 0}

⤑ \tt{ {x}^{2}  + 11x + 5x +  55 = 0}

⤑ \tt{x(x + 11) + 5(x + 11) = 0}

⤑ \tt{(x + 5)(x + 11) = 0}

Either :

\tt{x + 5 = 0 \: \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \: Or :  \:  \:  x + 11 = 0}

\sf{⟶ x  = 0 - 5} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    \:⟶  x =  0 - 11

\tt{⟶x =  - 5 } \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:     \:  \:⟶   x =  - 11

\red{ \boxed{ \boxed{ { \tt{Our \: final \: answer :  \boxed{ \underline{  \bold{ \tt{x  =  - 5 \: , - 11}}}}}}}}}

Hope I helped ! ♡

Have a wonderful day / night ! ツ

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

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Please help xxxxxxxx
Free_Kalibri [48]

Answer:

  • a. \bold{45000\times \:10^7}
  • b. \bold{3500}

Step-by-step explanation:

a. \left(5\times \:10^3\right)\left(9\times \:10^7\right)

5\times 10^3 = 5000\\\\5000\times \:9\times \:10^7

\mathrm{Multiply\:the\:numbers:}\:5000\times \:9=45000

=45000\times \:10^7

b. \left(7\times 10^5\right)\div \left(2\times 10^2\right)

\left(7\times 10^5\right)\div \left(2\times 10^2\right)=\frac{7\times \:10^5}{2\times \:10^2}

\frac{10^5}{10^2} = 10^3

\frac{7\times \:10^3}{2}

\mathrm{Factor}\:\: 10^3 : 2^3\times5^3

\frac{7\times \:2^3\times \:5^3}{2}

\frac{2^3}{2}=2^2

7\times \:2^2\times \:5^3=3500

7 0
3 years ago
Find the square roots by division method of 210,681 please tell me
padilas [110]

Answer:

  459

Step-by-step explanation:

The "long division method" algorithm for square root makes use of the relation described by the square of a binomial.

  (a +b)² = a² +2ab +b² = a² +b(2a +b)

<h3>Steps</h3>

The value for which the root is desired is written with digits marked off in pairs either side of the decimal point.

The initial digit of the root is the integer part of the square root of the most-significant pair. Here that is floor(√21) = 4. This is shown in the "quotient" spot above the leftmost pair. The square of this value is subtracted, and the next pair brought down for consideration. Here, that means the next "dividend" is 506.

The next "divisor" will be 2 times the "quotient" so far, with space left for a least-significant digit. Here, that means 506 will be divided by 80 + some digits. As in regular long division, determining the missing digit involves a certain amount of "guess and check." We find that the greatest value 'b' that will give b(80+b) ≤ 506 is b=5. This is the next "quotient" digit and is placed above the "dividend" pair 06. The product 5(85) = 425 is subtracted from 506, and the next "dividend" pair is appended to the result. This makes the next "dividend" equal to 8181.

As in the previous step, the next "divisor is 2 times the quotient so far: 2×45 = 90, with space left for the least significant digit. 8181 will be divided by 900-something with a "quotient" of 9. So, we subtract the product 9(909) = 8181 from the "dividend" 8181 to get the next "dividend." That result is zero, so we're finished.

The root found here is 459.

__

<em>Additional comment</em>

In practice, roots are often computed using iterative methods, with some function providing a "starter value" for the iteration. Some iterative methods can nearly double the number of good significant digits in the root at each iteration.

Using this "long division method," each "iteration" adds a single significant digit to the root. Its advantage is that it always works, and is generally suitable for finding roots by hand. Once the number of root digits begins to get large, the "divisor" starts to be unwieldy.

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2 years ago
Which statements are true? Check all that apply.
mariarad [96]

Answer:

A, B, and C

Step-by-step explanation:

A) We can see if this is a horizontal line if its slope is 0. Slope is change in y divided by change in x, so: slope = \frac{7-7}{3-(-2)} =\frac{0}{5} =0 . Thus, this is a horizontal line and the statement is correct.

B) Any equation of the form x = k, where k is a constant, will always be a straight line. Let's see if it goes through (-8, 3) by plugging in the values of -8 in for x and 3 in for y in the equation.

Clearly, we don't have a y, so we just put in the -8 for the x: -8 = -8. Since this is a true statement, we know that x = -8 does go through (-8, 3). So, this is a true statement.

C) We can see if this is a vertical line if its slope is undefined (for example, if the denominator is 0, it's undefined). Slope = \frac{5-(-7)}{0-0} =\frac{12}{0} = undefined. So, this is a vertical line and the statement is true.

D) As a basic fact, any point on a horizontal line will have the same y coordinate. However, their x coordinates may vary. Thus, the statement is false.

So, the answers are A, B, and C.

Hope this helps!

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Answer:

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Step-by-step explanation:

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Area Triangle = 1/2 * 8 * 4

Area Triangle = 1/2 32

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