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2 years ago

Answer questions 5-9 please

Mathematics

1 answer:

WITCHER [35]2 years ago

8 0

Answer: 5. B

6. eh

7. ac

8. vlm

9. frs

Step-by-step explanation:

The squiggle inbetween the groups of letters means congruent, or equal to. So if triangle abc is the same as triangle meh, then the length between a and b of the first triangle must be equivalent to the length between m and e of the second triangle (LETTER ORDER IS IMPORTANT)

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Greta is trying to determine the portion of green candies in various bags of green and yellow candies. Using the information bel

IrinaK [193]

Answer: a) $\dfrac{1}{3}$ b) $\dfrac{71}{100}$ c) $\dfrac{5}{9}$

Step-by-step explanation:

Since we have given that

There are green and yellow candies in each bag.

Bag A: Two thirds of the candies are yellow. What portion of the candies is green?

Part of yellow candies in bag A = $\dfrac{2}{3}$

Part of green candies in bag A would be

$1-\dfrac{2}{3}\\\\=\dfrac{3-2}{3}\\\\=\dfrac{1}{3}$

Bag B: 29 % of the candies are yellow. What portion of the candies is green?

Percentage of candies are yellow = 29%

Portion of candies are green is given by

$1-\dfrac{29}{100}\\\\=1-0.29\\\\=0.71\\\\=\dfrac{71}{100}$

Bag C: 4 out of every 9 candies are yellow. What portion of the candies is green?

Portion of yellow candies = $\dfrac{4}{9}$

Portion of green candies would be

$1-\dfrac{4}{9}\\\\=\dfrac{9-4}{9}\\\\=\dfrac{5}{9}$

Hence, a) $\dfrac{1}{3}$ b) $\dfrac{71}{100}$ c) $\dfrac{5}{9}$

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2 years ago

Write the average of y numbers. Is 22 the numbers 20, 17, 24, 18, 29 and x. find x

Elena L [17]

22 is the average of the numbers 20,17,24,18,29, and x is what I guess the qusetion is

count them
6 numbers

(20+17+24+18+29+x)/6=22
(108+x)/6=22
times both sides by6 to clear fraction
108+x=132
minus 108 from both sides
x=24

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2 years ago

a chef uses 4 3/4 cups of broth for 10 servings of soup.how much broth is is one serving . let x represent amount. 4 3/4/10 =x/1

enyata [817]

Let's firstly convert the mixed fraction to "improper" and then proceed,

$\bf \begin{array}{ccll}
\stackrel{broth}{cups}&servings\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
4\frac{3}{4}&10\\\\
x&1
\end{array}\implies \cfrac{\quad \stackrel{mixed}{4\frac{3}{4}}\quad }{x}=\cfrac{10}{1}\implies \cfrac{\quad \frac{4\cdot 4+3}{4}\quad }{x}=\cfrac{10}{1}$

$\bf \cfrac{\quad \stackrel{improper}{\frac{19}{4}}\quad }{x}=\cfrac{10}{1}\implies \cfrac{\quad \frac{19}{4}\quad }{\frac{x}{1}}=\cfrac{10}{1}\implies \cfrac{19}{4}\cdot \cfrac{1}{x}=\cfrac{10}{1}\implies \cfrac{19}{4x}=\cfrac{10}{1}
\\\\\\
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