The class has 28 student. One group has four more students so surat 4 from 28. 28-4=24 since one of the groups have twice as many students as the other divide 24 by 3. 24 / 3 = 8. It says 1 group has for more than twice the other group so that would mean 2/3 of 24 and 4 would be the answer 16+4=20. The first group had 8 students, the other group has 20 students.
Answer:
x = 1, -5.56
Step-by-step explanation:
x^2 = -7x - 8
shift -7x and -8 to the other side . Remember when u shift minus changes into plus.
x^2 + 7x + 8 = 0
using quadratic equation formula
in quadratic equation one value comes positive and other comes in negative
a = 1 , b = 7 and c = 8
taking positive sign
x = (-b + 
) /2*a
x = (-7 + 
) /2*1
x = (-7 + 
) /2
x = (-7 + 
)/ 2
x = -7 + 9 / 2
x = 2/2
x = 1
taking negative sign
(-b - ) /2*a
x = (-7 - ) /2*1
x = (-7 - 
) /2
x = -7 - 
/ 2
x = -7 - 4.12 / 2
x = -11.12/2
x = -5.56
therefore x = 1 , - 5.56
N = 3 ( the next number is 3 plus the previous number
sequence formula = an = 3(n-1) +2
so for term the term that =59
59 = 3(n-1) +2
distribute:
59 = 3n -3+2
59 = 3n -1
60 = 3n
n = 60/3
n = 20
59 is the 20th term
Answer:
Step-by-step explanation:
Total number of tickets sold = 3388
Total number of coach tickets = 3069
Total number of first-class tickets = Total number of tickets sold - Total number of coach tickets
= 3388 - 3069
= 319
Ratio of the number of first-class tickets to the total number of tickets = 319:3388
For a smoothing constant of 0.2
Time period – 1 2 3 4 5 6 7 8 9 10
Actual value – 46 55 39 42 63 54 55 61 52
Forecast – 58 55.6 55.48 52.18 50.15 52.72 52.97 53.38 54.90
Forecast error - -12 -.6 -16.48 – 10.12 12.85 1.28 2.03 7.62 -2.9
The mean square error is 84.12
The mean forecast for period 11 is 54.38
For a smoothing constant of 0.8
Time period – 1 2 3 4 5 6 7 8 9 10
Actual value – 46 55 39 42 63 54 55 61 52
Forecast – 58 48.40 53.68 41.94 41.99 58.80 54.96 54.99 59.80
Forecast error - -12 6.60 -14.68 0.06 21.01 -4.80 0.04 6.01 -7.80The mean square error is 107.17
The mean forecast for period 11 is 53.56
Based on the MSE, smoothing constant of .2 offers a better model since the mean forecast is much better compared to the 53.56 of the smoothing constant of 0.8.
