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2 years ago

8

Derrick has a very long rope. He used 3/8 of it to make some outdoor structures. He cut the remainder up into 15 equal short rop

es. He used 10 of these to tie some parcels. He measured and realized that he was left with 7 1/2m of rope left. how long was the rope originally?

1 answer:

Pepsi [2]2 years ago

6 0

Answer:afafafaf

Step-by-step explanation:

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Solve the simultaneous equations:<br><br> 5x + 3y = 9<br> 7x - 2y = 25<br><br> x=__<br> y=__

kondor19780726 [428]

Answer:

x= 3, y= -2

Step-by-step explanation:

5x+3y= 9

x= 25÷7 + 2÷7 y

5(25÷7 +2÷7 y)

5( 25÷7 +2÷7 y ) + 3y= 9

y= -2

x= 25÷7 + 2÷7 x (-2)

x= 3

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2 years ago

Tickets to a local circus cost $5 for students and $8 for adults. A group of 9 people spent a total of $60. How many adults were

S_A_V [24]

Answer:

5

Step-by-step explanation:

You need to set up and solve a system of linear equations here.

Let s and a represent the number of students and adults respectively.

Then s + a = 9, and s = 9 - a.

Total ticket cost for the adults was ($8/adult)(a)

and for the students ($5/student)(s).

Total cost of the tickets was then ($8/adult)(a) + ($5/student)(s) = $60.

Then our system of linear equations is:

8a + 5s = 60

a + s = 9, or s = 9 - a. Substituting 9 - a for s, we get:

8a + 5(9 - a) = 60.

Then 8a + 45 - 5a = 60, or 3a = 15.

Solving for a, we get a = 5.

Solving for s using s = 9 - a, we get s = 9 - 5, or s = 4.

There were 5 adults in the group (and 4 students).

3 0

2 years ago

Solve 2x+ 3=7<br> please

blondinia [14]

2x+3=7

2x+3-3=7-3

Whenever moving a number to the other side you have to change the sign .

2x= 4

x=2

7 0

3 years ago

Please show me how to solve the initial value problem <br> y'=tanx y(pi/4)=3

AlexFokin [52]

The ODE is separable, i.e. you can write

$\dfrac{\mathrm dy}{\mathrm dx}=\tan x\iff\mathrm dy=\tan x\,\mathrm dx$

Integrating both sides gives the general solution.

$\displaystyle\int\mathrm dy=\int\tan x\,\mathrm dx$
$y=-\ln|\cos x|+C$

Given that $y\left(\dfrac\pi4\right)=3$ , we have

$3=-\ln\left|\cos\dfrac\pi4\right|+C$
$3=-\ln\dfrac1{\sqrt2}+C$
$3-\ln\sqrt2=C$

and so the particular solution to the IVP is

$y=-\ln|\cos x|+3-\ln\sqrt2$
$y=3-\ln|\sqrt2\cos x|$

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3 years ago

Monica graphed the line y=3×+2.Janice graphs the second line that is parallel to monica's and passes through (-2,0). What is the

rewona [7]

The equation of a line that passes throug the point (x1,y1) and has a sloppe of m is
y-y1=m(x-x1)

the slope of paralell lines ar the same

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y=mx+b
m=slope
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a point is (-2,0)
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y-0=3(x-(-2))
y=3(x+2)
y=3x+6
the equation is y=3x+6

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2 years ago