The volume of aggregate that she needs to build the patio is 13.18 ft^3
<h3>How many cubic feet of aggregate would she need to build the walkway?</h3>
We know that the backyard is 14ft long, 6 feet wide and 4 inches deep.
Rememeber that:
1ft = 12 in
Then:
4 in = (4/12) ft = (1/3) ft
Then the volume of the backyard is:
V = (14ft)*(6ft)*(1/3 ft) = 28ft^3
Now we know that we have a mix of 4 parts aggregate to 4.5 parts loose cement that need to fill these 28 cubic feet.
Note that:
4 + 4.5 = 8.5
How many times we have 8.5 in 28?
28/8.5 = 3.294
Now for each of these we have 4 parts of aggregate, then the volume of aggregate that we need is:
4*3.294 ft^3 = 13.18 ft^3
The volume of aggregate that she needs to build the patio is 13.18 ft^3
If you want to learn more about volumes:
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I think false.
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Velocity the speed AND direction of something.
.
you run AROUND a track, so the direction changes. Thus velocity changes.
Answer:
8m(4+7p)
Step-by-step explanation:
32m = 4*8*m
56 mp = 7*8*m*p
We can factor out an 8m. What is left goes inside the parentheses
32m + 56mp
8m(4+7p)
Answer:
8
Step-by-step explanation:
5V-6W
V=4. W=2.
5(4)-6(2)
20-6(2)
20-12=
8
Answer:
6400 fans will be pleased.
Step-by-step explanation:
Out of 150 fans, 120 were pleased. Assuming the same ratio, out of 8000 fans, 8000x120/150 = 6400 will be pleased.
