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3 years ago

Help please !!!! I’ll give u brainliest

Mathematics

2 answers:

likoan [24]3 years ago

6 0

Answer:

they all have 3 points seeeee

monitta3 years ago

5 0

Answer:

They all have a right angle

Step-by-step explanation:

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The equation of the line shown in the graph is y = ?.

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Equation if the line for the graph is
y = -2x+1

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3 years ago

In triangle MNO the measure of

almond37 [142]

Where's the triangle? Thanks!

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3 years ago

On what intervals is the graph of f(x)=x^3-2x^2+5x+1 increasing?

amid [387]

$f(x)=x^3-2x^2+5x+1\\ f'(x)=3x^2-4x+5\\
3x^2-4x+5=0\\\Delta=(-4)^2-4\cdot3\cdot5=16-60=-44$
$\Delta0 \Rightarrow$ the graph of the parabola is above the x-axis, so the derivative is always positive and therefore the initial function is increasing in its whole domain.

$f(x)=0.5x^2-6\\
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3 0

4 years ago

Please help me with #31<br> I will give 13 points it’s not much but I really need help

olganol [36]

Answer:

i think it might be 10 im sorry if im wrong

Step-by-step explanation:

The perimeter of a circle is π × d where d is the diameter so half of that is 1/2 π × d. But If you are going to walk around a semicircle you need to go half way around the circle and then across a diagonal to get back to where you started so the perimeter is 1/2 π × d + d.

6 0

3 years ago

Read 2 more answers

Show that ∆ABC is a right triangle if A(0, 0), B(3, 2), and C(–2, 3). Find the slope m1 of AB and the slope m2 of AC and verify

Mariana [72]

First we'll show this is a right triangle by the Pythagorean Theorem:

$A(0,0), B(3,2), C(-2, 3)$

$AB^2=3^2+2^2=13$

$AC^2=(-2)^2+3^2=13$

$BC^2 = (-3 -3)^2 + (3 -2)^2 = 26$

Since $AB^2+AC^2=BC^2$ we have a right triangle, by the (converse to the) Pythagorean Theorem. We also see it's isosceles, AB=AC.

$\textrm{Slope of AB} = m_1 = \dfrac{2 - 0}{3 - 0} = \dfrac 2 3$

$\textrm{Slope of AC} = m_2 = \dfrac{3 - 0}{-2 - 0} = -\dfrac 3 2$

$m_1 m_2 = (\frac 2 3)(-\frac 3 2 ) = -1 \quad\checkmark$

That's the end of the homework but I'll go on a bit.

Another way to show perpendicularity, essentially the same as the other two, is by a zero as the dot product of the sides as vectors, differences between vertices.

Vector AB = B - A = (3,2)

Vector AC = C - A = (-2, 3)

AB · AC = 3(-2) + 2(3) = 0

A zero dot product means

AB ⊥ AC

8 0

3 years ago