Well (3-2^2)5 = -5
and 5-3^2=-4
5-2^2=1
2^2-5=-1
3^2-5=4
but if you have to multiply them by 5 as well then (2^2-5)5=-5
Answer:

Step-by-step explanation:

ΔJKL and ΔXYZ CANNOT be congruent triangles because: the hypotenuse of one triangle is equal in length to the leg of the other triangle.
<h3>What are Congruent Triangles?</h3>
Congruent triangles are triangles whose corresponding sides are congruent to each other.
The hypotenuse of triangle JKL(KL = 10) is congruent to a leg of triangle XYZ (YX = 10). This implies that they cannot be congruent triangles.
Therefore, ΔJKL and ΔXYZ CANNOT be congruent triangles because: the hypotenuse of one triangle is equal in length to the leg of the other triangle.
Learn more about congruent triangles on:
brainly.com/question/11457412
Answer:
z= 13
x= 36
y= 18
Step-by-step explanation:
Solving for z.
We know that 108 degrees and (8z+4) are alternate exterior angles, so they are equal to each other.
We can set both of those angles equal to each other, and solve for our missing side, z.
108= 8z+4
104=8z
z= 13
Solving for x.
We know that 108 degrees and (3x) are alternate interior angles, so they would equal each other.
We can set both of these angles equal to each other, and solve for our missing side, x.
3x=108
x= 36
Solve for y.
We know that (4y) and (3x) are same side interior angles, so they would make 180 degrees. We know that (3x) would equal 108.
4y+108=180
4y= 72
y= 18