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Zolol [24]
1 year ago
12

Triangles J K L and X Y Z are shown. Angles K J L and Y X Z are right angles. The length of Y X is 10. The length of hypotenuse

K L is 10.
Could ΔJKL be congruent to ΔXYZ? Explain.

Yes, if JL ≅ XZ.
Yes, if XZ = 10.
No, because the hypotenuse of one triangle is equal in length to the leg of the other triangle.
No, because the leg of one triangle is equal in length to the leg of the other triangle.
Mathematics
1 answer:
pickupchik [31]1 year ago
3 0

ΔJKL and ΔXYZ CANNOT be congruent triangles because: the hypotenuse of one triangle is equal in length to the leg of the other triangle.

<h3>What are Congruent Triangles?</h3>

Congruent triangles are triangles whose corresponding sides are congruent to each other.

The hypotenuse of triangle JKL(KL = 10) is congruent to a leg of triangle XYZ (YX = 10). This implies that they cannot be congruent triangles.

Therefore, ΔJKL and ΔXYZ CANNOT be congruent triangles because: the hypotenuse of one triangle is equal in length to the leg of the other triangle.

Learn more about congruent triangles on:

brainly.com/question/11457412

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Thepotemich [5.8K]

Answer:

Total compensation = 600 + 0.04 * s  and a total last month of $1200

(which agrees with the second answer shown in the provided list)

Step-by-step explanation:

Total compensation comes from the addition of base salary ($600) plus 4% (0.04) of the sales (s). That means:

Total compensation = 600 + 0.04 * s

and since last month he brought $15000 in sales, he got from sales:

0.04 * 15000 = $600

which added to the base salary gives:

$600 + $600 = $1200

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2 years ago
Use substitution to solve the following system of linear equations and fill in the following blanks:
marissa [1.9K]

Answer:

x=-4

y=3

z=-5

Step-by-step explanation:

<u>Given:</u>

x+y+z=-6

x-6y-7z=-29

-7y-5z=4

<u>Solve for </u>x<u> in the 1st equation:</u>

x+y+z=-6

x+y=-z-6

x=-y-z-6

<u>Substitute the value of </u>x<u> into the 2nd equation and solve for </u>z<u>:</u>

x-6y-7z=-29

(-y-z-6)-6y-7=-29

-7y-z-13=-29

-7y-z=-16

-z=-16+7y

z=16-7y

<u>Substitute the value of </u>z<u> into the 3rd equation and solve for </u>y<u>:</u>

-7y-5z=4

-7y-5(16-7y)=4

-7y-80+35y=4

28y-80=4

28y=84

y=3

<u>Plug </u>y=3<u> into the solved expression for </u>z<u> and evaluate to solve for </u>z<u>:</u>

z=16-7(3)

z=16-21

z=-5

<u>Plug </u>z=-5<u> into the solved expression for </u>x<u> and evaluate to solve for </u>x<u>:</u>

x=-(3)-(-5)-6

x=-3+5-6

x=2-6

x=-4

Therefore:

x=-4

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3 years ago
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(9w +2) - (7w+6)

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What is the solution to the system of equations?
melamori03 [73]

Answer:

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3 years ago
Find the lateral area of the regular pyramid<br><br> L.A. =
Arisa [49]

Answer:

FOR REGULAR PYRAMID with those dimension.

L.A = 96

FOR HEXAGONAL PYRAMID with those dimension

L.A = 171.71

Step-by-step explanation:

Please the question asked for L.A of a REGULAR PYRAMID, but the figure is a HEXAGON PYRAMID.

Hence I solved for both:

FOR REGULAR PYRAMID

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P = 4s

P = 4 * 6

P = 24cm

l = slanted height

l = 8cm

L.A = 1/2 * 24 * 8

L.A = 1/2 ( 192)

L.A = 96cm ^ 2

FOR AN HEXAGONAL PYRAMID

Lateral Area = 3a √ h^2 + (3a^2) / 4

Where:

a = Base Edge = 6

h = Height = 8

L.A = 3*6 √ 8^2 + ( 3*6^2) / 4

L.A = 18 √ 64 + ( 3 * 36) / 4

L.A = 18 √ 64 + 108/4

L.A = 18 √ 64+27

L.A = 18 √ 91

L.A = 18 * 9.539

L.A = 171.71

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2 years ago
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