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Pani-rosa [81]
3 years ago
14

Why might a student be proud if he or she memorized a famous speech?​

Mathematics
1 answer:
quester [9]3 years ago
4 0

A student might be proud if he or she memorized a famous speech because it might mean a lot to them in a way. Memorizing a famous speech can have an impact on you and your life. That’s why there are famous speeches for a reason.

Hoped I help, plz mark as brainliest. If you can. :)

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Which of the following is the standard equation of the ellipse with vertices at (1,0) and (27,0) and an eccentricity of 5/13?
Dovator [93]

The equation of the elipse is given by:

\frac{(x - 14)^2}{169} + \frac{y^2}{144} = 1

The equation of an elipse of center (x_0, y_0) is given by:

\frac{(x - x_0)^2}{a^2} + \frac{(y - y_0)^2}{b^2} = 0

Values a and b are found according to the <u>vertices and the eccentricity</u>.

It has vertices at (1,0) and (27,0), thus:

x_0 = \frac{27 + 1}{2} = 14

y_0 = \frac{0 + 0}{2} = 0

a = \frac{27 - 1}{2} = 13

a^2 = 169

It has eccentricity of \frac{5}{13}, thus:

\frac{5}{13} = \frac{c}{a}

\frac{5}{13} = \frac{c}{13}

c = 13

Thus, b is given according to the following equation:

c^2 = a^2 - b^2

b^2 = a^2 - c^2

b^2 = 169 - 25

b = \sqrt{144}

b = 12

The equation of the elipse is:

\frac{(x - 14)^2}{169} + \frac{y^2}{144} = 1

A similar problem is given at brainly.com/question/21405803

3 0
3 years ago
Whats 600 divied by 300
kolbaska11 [484]

Answer:

2

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
What is equivalent to k/2​
Mazyrski [523]

Answer:

k x 1/2

Step-by-step explanation:

because k x 1/2 = k/2

8 0
2 years ago
Morgan begins biking south to the park at 20mph at noon. Corona leaves from the same point 15 min (.25hr) later to catch her. Ho
garri49 [273]

Answer:

X = 1h15mins

Step-by-step explanation:

      Rate Time  Distance  

Morgan  20    X              20X

Corona  25  X – ¼  25(X – ¼)  

If they meet each other, they need to travle the same distance, mean :  

20X = 25(X – ¼)  

X = 1.25  

1 hour and 15 minutes  

6 0
3 years ago
A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at th
Valentin [98]

Answer:

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=12.8

The sample deviation calculated s=4.324 \approx 4.3

12.8-4.604\frac{4.324}{\sqrt{5}}=3.896    

12.8+ 4.604\frac{4.324}{\sqrt{5}}=21.704    

So on this case the 99% confidence interval would be given by (3.896;21.704)    

Step-by-step explanation:

Data: 10,9,20,13,12

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=12.8

The sample deviation calculated s=4.324

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=5-1=4

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,4)".And we see that t_{\alpha/2}=4.604

Now we have everything in order to replace into formula (1):

12.8-4.604\frac{4.324}{\sqrt{5}}=3.896    

12.8+ 4.604\frac{4.324}{\sqrt{5}}=21.704    

So on this case the 99% confidence interval would be given by (3.896;21.704)    

6 0
3 years ago
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