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Igoryamba
2 years ago
11

The ratio of the sides of a triangle is 8:13:11. If the perimeter of a triangle is equal to 256, what is the length of the longe

st side?
Mathematics
1 answer:
s344n2d4d5 [400]2 years ago
6 0
There asking what the numbers are by The ratios, what I did was did was multiply by 8 for each number 8•8=64 13•8=104 11•8=88 so now what you do is add up 64+104+88=256 those are your answers if you want to double check you will dived them by 8 so 64/8=8 104/8=13 88/8=11
Hope this helps :-)
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Answer:

The answer is,

(8+2+6) ft = 16 ft

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3 years ago
Neil has 3 partially full cans of white paint.They contain 1/3 gallon,1/5 gallon,and 1/2 gallon of paint.About how much paint do
Wittaler [7]

Answer:

  less than 1 1/2 gallons

Step-by-step explanation:

1/3 + 1/6 = 1/2, so the sum of the three cans is more than 1 by the difference between 1/5 and 1/6. That difference is 1/30 gallon. The sum is 1 1/30 gallons, which is less than 1 1/2 gallons.

__

A suitable common denominator is 2·3·5 = 30. Then the sum of the fractions is ...

  1/3 + 1/5 + 1/2

  = 10/30 + 6/30 + 15/30

  = 31/30 = 1 1/30 . . . . . less than 1 1/2

In decimal, 1/3 ≈ 0.333, 1/5 = 0.200, 1/2 = 0.500, so the sum is ...

  0.333 +0.200 +0.500 = 1.033

which is less than 1.5.

4 0
3 years ago
Question 1 (1 point) Question 1 Unsaved
QveST [7]
en la cocina (where is the dishwasher? the kitchen)
7 0
3 years ago
31.75 as a improper and mixed fraction
Aleksandr [31]
31.75 as an improper fraction is 127/4. The mixed number fraction is 31 3/4.
3 0
3 years ago
The population of a colony of mosquitoes obeys the law of uninhibited growth. If there are 1000 mosquitoes initially and there a
Anettt [7]

Answer:

1) The size of the colony after 4 ​days is 6553 mosquitoes

2) After t = 4.9\ days

Step-by-step explanation:

To answer this question you must use the growth formula

N = N_0e ^ {kt}

Where

N_0 is the initial population of mosquitoes = 1000

t is the time in days

k is the growth rate

N is the population according to the number of days

We know that when t = 1 and N_0=1000 then N = 1600

Then we use these values to find k.

1600 = 1000e ^{k(1)}\\\\\frac{1600}{1000} = e ^ k\\\\ln(\frac{1600}{1000}) = k\\\\k = 0.47

Now that we know k we can find the size of the colony after 4 days.

N = 1000e ^ {0.47(4)}\\\\N = 6553\ mosquitoes

To know how long it should take for the population to reach 10,000 mosquitoes we must do N = 10000 and solve for t.

10000 = 1000e ^ {0.47t}\\\\10 = e ^ {0.47t}\\\\ln(10) = 0.47t\\\\t = \frac{ln(10)}{0.47}\\\\t = 4.9\ days

6 0
3 years ago
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