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3 years ago

14

PLEASE HELP ME QUICK!!!!!

1 answer:

Alex777 [14]3 years ago

5 0

Answer:

because its out of 100

Step-by-step explanation:

cause it could be something else

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How do I solve w(x)=4x+5; find w(-8)?

madam [21]

W(x) = 4x + 5

w(-8) = 4(-8) + 5 = -32 + 5 = -27

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4 years ago

Which of the following would best be solved using factoring the difference of squares? 2² + 3x - 10 = 0 O 3r² + 12x = 8 2³ +52²

IgorC [24]

Given: Different equations

To Determine: Which would be best solved using difference of two squares

Solution

The factorization of a difference of two squares is given below

$a^2-b^2=(a-b)(a+b)$

Let us examine each of the given equation

$\begin{gathered} x^2+3x-10=0 \\ x^2-2x+5x-10=0 \\ x(x-2)+5(x-2)=0 \\ (x-2)(x+5)=0 \end{gathered}$ $\begin{gathered} 3x^2+12x=8 \\ 3x^2+12x-8=0 \end{gathered}$ $\begin{gathered} x^3+5x^2-9x-45=0 \\ x^2(x+5)-9(x+5)=0 \\ (x+5)(x^2-9)=0 \\ x^2-9=x^2-3^2=(x+3)(x-3) \\ Therefore \\ (x+5)(x+3)(x-3)=0 \end{gathered}$ $\begin{gathered} x^2-25=0 \\ x^2-5^2=0 \\ (x+5)(x-5)=0 \end{gathered}$

From the above,

$\begin{gathered} x^3+5x^2-9x-45=0 \\ AND \\ x^2-25=0 \end{gathered}$

The two equation above can be solved by difference of two square, but the equation below is the easiest solved using differnce of two square

x² - 25 = 0

3 0

1 year ago

Solve the system of equations

agasfer [191]

D<span>here, we go by the same exact principle, but the terms are not a,b,c.
</span>

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3 years ago

A police car's siren operates at a frequency of 2,000 Hz. What frequency would a stationary listener observe if the police car i

SpyIntel [72]

we can use formula

$f_L=f_s(\frac{v_a-v_p}{v_a+v_p} )$

where

fL is listener frequency

fs is siren frequency

va is the speed of sound in air

vs is police car speed

so, we have

$f_s=2000Hz$

$v_a=345m/s$

$v_p=65mph$

now, we can change it into m/s

$v_p=65*\frac{1609}{3600}m/s$

$v_p=29.05139m/s$

now, we can plug it

$f_L=2000(\frac{345-29.05139}{345+29.05139} )$

$f_L=1689.33263Hz$ ..............Answer

3 0

3 years ago

If exactly 194 people sign up for a charter flight, Leisure World Travel Agency charges $312/person. However, if more than 194 p

maw [93]

Title:

<h2>The revenue will be maximum for 253 passengers.</h2>

Step-by-step explanation:

Let, the number of passenger is x, which is more than 194.

In this case, the travel agency will charge [312 - (x - 194)] per passenger.

The total revenue will be $x[312 - (x - 194)] = 506x - x^{2}$ .

As x is the variable here, we can represent the revenue function by R(x). Hence, $R(x) = 506x - x^{2}$ .

The revenue will be maximum when $\frac{d (506x - x^{2} )}{dx} = 0\\2x = 506\\x = 253$ .

6 0

3 years ago