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s344n2d4d5 [400]
3 years ago
14

How do i solve 8/9x=24

Mathematics
1 answer:
qwelly [4]3 years ago
7 0
By multiplying both sides by the reciprocal of 8/9x
so 24 x 9/8x
this singles out the x and gives you
x = 27
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A 55m and 35m broad park is surrounded by a 2.5m wide path.
daser333 [38]

Step-by-step explanation:

☄ \underline {\underline{ \text{Given}}} :

  • Length of a park ( l ) = 55 m
  • Breadth of a park ( b ) = 35 m
  • Width running outside the park ( d ) = 2.5 m
  • Rate of paving the path with stones = Rs 120 per sq.metre

☄ \underline{ \underline{ \text{To \: find}}}:

  • Area of the park
  • Cosy of paving the path with stones at Rs 130 per sq.metre

☄ \underline{ \underline{ \text{Solution}}} :

Part 1 : \boxed{\text{Area \:of \:a \:path \: running \:outside = 2d(l + b + 2d)}}

plug the known values and simplify :

⟹ \sf{2 \times 2.5(55 + 35 + 2 \times 2.5)}

⟹ \sf{5  \times 95}

⟹ \sf{475 \:  {m}^{2} }

Part 2 : \boxed{ \sf{Total \: cost = Area \: of \: paths \:  \times  Rate}}

⟹ \sf{475  \times 120}

⟹\sf{Rs \: 57000}

\purple{ \boxed{ \boxed{ \sf{ \tt{⟿ \: Our \: final \: answer : (i) = 475 \:  {m}^{2}   \:  and \: (ii ) = Rs \: 57000}}}}}

Hope I helped ! ♡

Have a wonderful day /night ツ

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7 0
3 years ago
2 Points
masya89 [10]
The answer is 120. Because inscribed angle is Half of the arc measure. Double 60 and we get 120.
6 0
4 years ago
Read 2 more answers
6. MONEY Len bought a $24.99 pair of pants
tatuchka [14]

Answer:

$2.06 tax

Step-by-step explanation:

$24.99 pants

$27.05 total cost with tax

24.99 + tax = 27.05

tax = 27.05 - 24.99

27.05 - 24.99 = 2.06

7 0
4 years ago
Carl is on the school track team. to prepare for an upcoming race, he plans to run 207 miles total over the next 31 days.
patriot [66]
Theres no answer to this promblem do you wanna add more
6 0
3 years ago
I need help I’m bad at math
Alina [70]
If you'd graph this function, you'd see that it's positive on [-1.5,0], and that it's possible to inscribe 3 rectangles on the intervals [-1.5,-1), (-1,-0.5), (-0.5, 1].

The width of each rect. is 1/2.

The heights of the 3 inscribed rect. are {-2.25+6, -1+6, -.25+6} = {3.75,5,5.75}.

The areas of these 3 inscribed rect. are (1/2)*{3.75,5,5.75}, which come out to:

{1.875, 2.5, 2.875}

Add these three areas together; you sum will represent the approx. area under the given curve on the given interval:  1.875+2.5+2.875 = ?
5 0
3 years ago
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