9514 1404 393
Answer:
(0, π/4] ∪ (π, 5π/4]
Step-by-step explanation:
Multiplying by 2 gives ...
cot(x) ≥ 1
The cotangent function decreases from ∞ to 1 in the domain (0, π/4], and again in the domain (π, 5π/4]. The solution is the union of these two intervals.
x ∈ (0, π/4] ∪ (π, 5π/4]
_____
(a, b] is interval notation for a < x ≤ b
<span>Ok. You would set up the problem like this: 32/x=64/100 and then cross multiply; 3200=64x; divide both sides by 64; x=50. Mary has 50 customers.</span>
6x + 1 = 2x + 10 + 79
6x + 1 = 2x + 89
4x = 88
x = 22
Answer:
option 1
Step-by-step explanation:
÷ 
• leave the first fraction
• change division to multiplication
• turn the second fraction 'upside down'
= × 
( cancel 5 and 10 by 5 )
= 
× 
= 
