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ad-work [718]
2 years ago
7

Which is greater? -1 17/20 or -1 8/10PLSSS HELP ASAPplsss show work aswell

Mathematics
1 answer:
wel2 years ago
6 0
-1 17/20 and -1 8/10 can be compared easily if we give them common denominators. If we multiply the second fraction by 2, both fractions will have a denominator of 20.

8 * 2 = 16
10 * 2 = 20
New fraction: 16/20

-1 17/20 vs. - 1 16/20

-1 16/20 (-1 8/10) is greater. (For negative numbers, you can tell which one is greater by determining which one is closest to zero.)
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256 km should be the answer
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Answer:

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Step-by-step explanation:

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2 years ago
A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u
Kryger [21]

Given: f(x) = \frac{1}{x-2}

           g(x) = \frac{2x+1}{x}

A.)Consider

f(g(x))= f(\frac{2x+1}{x} )

f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}

f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}

f(\frac{2x+1}{x} )=\frac{x}{1}

f(\frac{2x+1}{x} )=1

Also,

g(f(x))= g(\frac{1}{x-2} )

g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{x }{1}

g(\frac{1}{x-2} )= x


Since, f(g(x))=g(f(x))=x

Therefore, both functions are inverses of each other.


B.

For the Composition function f(g(x)) = f(\frac{2x+1}{x} )=x

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Therefore, the domain is (-\infty,0)\cup(0,\infty)


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Since, the function g(f(x)) is not defined for x=2.

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8 0
3 years ago
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Answer: 501, 511

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