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ioda
3 years ago
12

Due Today

Mathematics
1 answer:
V125BC [204]3 years ago
3 0

Answer:

its 11/4.5

Step-by-step explanation:

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HELP PLEASE!! I WILL MARK BRAINLIST
ankoles [38]

Answer:

D

Step-by-step explanation:

Have a nice day :)

7 0
3 years ago
30 POINTS If you help.....
Flauer [41]

Answer:

0.075

Step-by-step explanation:

<u>Step 1:  Make the denominator a whole number</u>

<u />\frac {0.48}{6.4}

\frac {0.48*5}{6.4*5}

\frac{2.4}{32}

<u>Step 2:  Divide</u>

<u />\frac{2.4}{32}

0.075

Answer:  0.075

4 0
4 years ago
After 2 years, a certain car is worth $16600. When it is 9 years old, the same car is then worth
Lubov Fominskaja [6]

The linear function that describes the situation is:

y = -950x + 18500.

  • The slope of -950 means that the price of the car decays $950 per year.
  • The y-intercept of 18500 means that the initial value of the car is of $18,500.
  • The x-intercept of 19.47 means that the value of car is of $0 after 19.47 years.

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

  • m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
  • b is the y-intercept, which is the value of y when x = 0.

In this problem, in 7 years, the price of the car decays by $6,650, hence the slope is given by:

m = -6650/7 = -950.

The slope of -950 means that the price of the car decays $950 per year.

Then, the equation is:

y = -950x + b.

After 2 years, a certain car is worth $16600, hence when x = 2, y = 16600, and:

16600 = -950(2) + b

b = 18500.

The equation is:

y = -950x + 18500.

The y-intercept of 18500 means that the initial value of the car is of $18,500.

The x-intercept is found when y = 0, hence:

-950x + 18500 = 0.

x = 18500/950

x = 19.47.

The x-intercept of 19.47 means that the value of car is of $0 after 19.47 years.

More can be learned about linear functions at brainly.com/question/24808124

8 0
2 years ago
Help me nowwwwwwwwwwwwwwwww
Alenkinab [10]

Answer:

volume = 3x6x2 = 36 cubic inches

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Please help me find out what the question marks are
quester [9]
Question a

g(x) times \sqrt{x-5}=\sqrt{x^2-5}
divide both sides by √(x-5)
g(x)=\frac{\sqrt{x^2-5}}{\sqrt{x-5}}
g(x)=\frac{(\sqrt{x-5})(\sqrt{x^2-5})}{x-5}
g(x)=\frac{\sqrt{x^3-5x^2-5x+25}}{x-5}


question b
g(x) \space\ times \space\ 1+\frac{1}{x}=x
divide both sides by 1+1/x
g(x)=\frac{x}{1+\frac{1}{x}}
times by x/x
g(x)=\frac{x^2}{x+1}


question c
\frac{1}{x} \space\ times \space\ f(x)=x
times both sides by x
f(x)=x^2


question d
the (f*g)(x) collumn seems to have a domain of only x is greater than or equal to 0?
so maybe we squared the whole thing, ya
wait
ah, ya
basically
|x|=(\sqrt{x})^2=(\sqrt{x})(\sqrt{x})
so f(x)=√x


a. g(x)=\frac{\sqrt{x^3-5x^2-5x+25}}{x-5}
b. g(x)=\frac{x^2}{x+1}
c.f(x)=x^2
d. f(x)=\sqrt{x}
3 0
4 years ago
Read 2 more answers
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