The answer is :
<span>A. Always
Also </span>
<span>If
two equations have different slopes but equivalent y-intercepts, they
will have one solution and that will be the point where the y-intercept
is. If two equations have different slopes and different y-intercepts,
then there will be one solution where those two lines meet. If two
equations have the same slope but different y-intercepts, the lines will
be parallel, and there is no possible intersection point. And if two
equations have equal slopes and equal y-intercepts, these lines will
have an infinite amount of solutions, because if the equations are one
the same line, every single point on that line is a solution to the
system. </span>
Adding (or subtracting) a constant to every data value adds (or subtracts) the same constant to measures of position such as center,percentiles, max or min.
Its shape and spread such as range, IQR, standard deviation remain unchanged.
When we multiply (or divide) all the data values by any constant, all measures of position (such as the mean, median, and percentiles) and measures of spread (such as the range, the IQR, and the standard deviation) are multiplied (or divided) by that same constant.
Part A:
The lowest score is a measure of location, so both addition and multiplying the lowest score of test B by 40 and adding 50 to the result will affect the lowest score of test A.
Thus, the lowest score of test A is given by 40(21) + 50 = 890
Therefore, the lowest score of test A is 890.
Part B:
The mean score is a measure of location, so both
addition and multiplying the mean score of test B by 40 and adding 50
to the result will affect the lowest score of test A.
Thus, the mean score of test A is given by 40(29) + 50 = 1,210
Therefore, the mean score of test A is 890.
Part C:
The standard deviation is a measure of spread, so multiplying the standard deviation of test B by 40 will affect the standard deviation but adding 50
to the result will not affect the standard deviation of test A.
Thus, the standard deviation of test A is given by 40(2) = 80
Therefore, the standard deviation of test A is 80.
Part D
The Q3 score is a measure of location, so both
addition and multiplying the Q3 score of test B by 40 and adding 50
to the result will affect the Q3 score of test A.
Thus, the Q3 score of test A is given by 40(28) + 50 = 1,170
Therefore, the Q3 score of test a is 1,170.
Part E:
The median score is a measure of location, so both
addition and multiplying the median score of test B by 40 and adding 50
to the result will affect the median score of test A.
Thus, the median score of test A is given by 40(26) + 50 = 1,090
Therefore, the median score of test A is 1,090.
Part F:
The IQR is a measure of spread, so multiplying the IQR of test B by 40 will affect the IQR but adding 50
to the result will not affect the IQR of test A.
Thus, the IQR of test A is given by 40(6) = 240
Therefore, the IQR of test A is 240.
Answer:
a) k = 5; (-10, -35)
Step-by-step explanation:
Given:
Co-ordinates:
Pre-Image = (-12,3)
After dilation
Image = (-60,15)
The dilation about the origin can be given as :
Pre-Image
where 
represents the scalar factor.
We can find value of for the given co-ordinates by finding the ratio of 
or 
co-ordinates of the image and pre-image.
For the given co-ordinates.
Pre-Image = (-12,3)
Image = (-60,15)
The value of 
or 
As we get 
for both ratios i.e of and co-ordinates, so we can say the image has been dilated by a factor of 5 about the origin.
To find the image of (-2,-7), after same dilation, we will multiply the co-ordinates with the scalar factor.
Pre-Image
Image
Pre-Image Image
(Answer)
Answer:
1/3
Step-by-step explanation:
I think not sure.
Answer:
See there is x° see the angle is right angle so
X = 90°
Y = 270°
