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vampirchik [111]
2 years ago
14

Two trials are conducted for an experiment. In Trial A, the measured value is 240, while the actual value is 200. In Trial B, th

e measured value is 195, while the actual value is 240. An assistant says that Trial B has the greater percent error. Is the assistant correct? Explain.
what the answer plz ???
Mathematics
1 answer:
Zepler [3.9K]2 years ago
5 0

Answer:

A is the answer 456% and 512%

Step-by-step explanation:

Percent Errors

Trial A

Trial B

Measured Value

240

195

Actual Value

200

240

Percent Error

​?

​?

Complete the table.

Percent Errors

Trial A

Trial B

Measured Value

240

195

Actual Value

200

240

Percent Error

440440​%

435435​%

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I think the answer is 41 over 100
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I would say C as the answer

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An English professor assigns letter grades on a test according to the following scheme. A: Top 14% of scores B: Scores below the
NeX [460]

Answer:

Grades between 62 and 64 result in a D grade.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 71.9, \sigma = 7.8

Find the numerical limits for a D grade.

D: Scores below the top 84% and above the bottom 10%

So below the 100-84 = 16th percentile and above the 10th percentile.

16th percentile:

This is the value of X when Z has a pvalue of 0.16. So X when Z = -0.995.

Z = \frac{X - \mu}{\sigma}

-0.995 = \frac{X - 71.9}{7.8}

X - 71.9 = -0.995*7.8

X = 64

10th percentile:

This is the value of X when Z has a pvalue of 0.1. So X when Z = -1.28.

Z = \frac{X - \mu}{\sigma}

-1.28 = \frac{X - 71.9}{7.8}

X - 71.9 = -1.28*7.8

X = 62

Grades between 62 and 64 result in a D grade.

6 0
3 years ago
Can someone please answer this question please answer it correctly and lease show work please help me I need it
earnstyle [38]

Answer:

C

Step-by-step explanation:

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Diano4ka-milaya [45]
Ok

first of all, for q(x)/p(x)
if the degree of q(x) is less than the degree of p(x),then the horizontal assemtote is 0

then simplify
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to find the vertical assemtotes of a function, set the SIMPLIFIED denomenator equal to 0 and solve

so

y=(x-5)/(x^2-1)
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no factors to simplify so no holes

set denomenator to 0 to find vertical assemtote
x^2-1=0
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