Answer: 1726
Step-by-step explanation:
A=2(wl+hl+hw)
A=
2
w
l
h
l
h
w
=
2
6.5
29
19
29
19
6.5
=
1726
Answer:Given:
P(A)=1/400
P(B|A)=9/10
P(B|~A)=1/10
By the law of complements,
P(~A)=1-P(A)=399/400
By the law of total probability,
P(B)=P(B|A)*P(A)+P(B|A)*P(~A)
=(9/10)*(1/400)+(1/10)*(399/400)
=51/500
Note: get used to working in fraction when doing probability.
(a) Find P(A|B):
By Baye's Theorem,
P(A|B)
=P(B|A)*P(A)/P(B)
=(9/10)*(1/400)/(51/500)
=3/136
(b) Find P(~A|~B)
We know that
P(~A)=1-P(A)=399/400
P(~B)=1-P(B)=133/136
P(A∩B)
=P(B|A)*P(A) [def. of cond. prob.]
=9/10*(1/400)
=9/4000
P(A∪B)
=P(A)+P(B)-P(A∩B)
=1/400+51/500-9/4000
=409/4000
P(~A|~B)
=P(~A∩~B)/P(~B)
=P(~A∪B)/P(~B)
=(1-P(A∪B)/(1-P(B)) [ law of complements ]
=(3591/4000) ÷ (449/500)
=3591/3592
The results can be easily verified using a contingency table for a random sample of 4000 persons (assuming outcomes correspond exactly to probability):
===....B...~B...TOT
..A . 9 . . 1 . . 10
.~A .399 .3591 . 3990
Tot .408 .3592 . 4000
So P(A|B)=9/408=3/136
P(~A|~B)=3591/3592
As before.
Step-by-step explanation: its were the answer is
4- 20
I created an equation for this one:
4x+x=100
- 4x= four times the amount of the other number
- x= the number
- combine like terms
5x=100
x=20
5. One pretzel costs $3
Create an equation:
Mulitply 2s+p=7 by -2 so you can use elimination.
Combine equations
p=3
Answer:
1) M(x) = 5 + 3x
2) Dependent variable; 3 dollar bills
Independent variable: chores
3) Range is continuous
Domain is discrete
4) Range: 0 ≤ x ≤ 10
Domain: 5 ≤ M ≤ 35
Step-by-step explanation:
We are told he started with 5 number of $1 dollar bills and that every Saturday, he earns 3 more $1 dollar bill.
Thus, total number of $1 bills earned after x number of Saturdays(weekly) is;
M(x) = 5 + 3x
After 10 weeks, total number is;
M(10) = 5 + 3(10)
M(10) = 35
The dependent variable is the 3 more dollar bills earned each Saturday because it depends on chores he completed. While the independent variable is the chores because it doesn't depend on anything.
After 10 weeks, the range and domain will be;
Range: 0 ≤ x ≤ 10
For the; Domain:
For x = 1, M(0) = 5 + 3(0) = 5
M(10) = 35
Thus;
Domain: 5 ≤ M ≤ 35
The range could be all numbers in the interval from 0 to 10. Thus, it is continuous.
Whereas, the domain doesn't contain all the numbers in the interval from 5 to 35. Thus it is Discrete.
Answer:
6+_3√2/2
Step-by-step explanation:
y=2x²-12x+9
y=6+3√2/2
