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3 years ago

8

If the function rule is 5x, what is the value when x=4

1 answer:

OleMash [197]3 years ago

6 0

20 will be the answer when x=4

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224

Step-by-step explanation:

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3 years ago

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Workout to the simplest:<br><img src="https://tex.z-dn.net/?f=%20%20%5Cint%20%5C%3A%20%20%7Bx%7D%5E%7B2%7D%20%20ln%28%20%7Bx%7D%

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How do I solve <img src="https://tex.z-dn.net/?f=sec%20-%202%5Cpi" id="TexFormula1" title="sec - 2\pi" alt="sec - 2\pi" align="a

olga2289 [7]

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2 years ago

It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp

Semmy [17]

Answer:

$\frac{1}{5}$

Step-by-step explanation:

Using the rules of exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$ , $\frac{a^{m} }{a^{n} }$ = $a^{(m-n)}$ , $(a^m)^{n}$ = $a^{mn}$

Simplifying the product of the first 2 terms

$\frac{a^{p^2+pq} }{a^{pq+q^2} }$ × $\frac{a^{q^2+qr} }{a^{qr+r^2} }$

= $a^{p^2-q^2}$ × $a^{q^2-r^2}$

= $a^{p^2-r^2}$

Simplifying the third term

5( $(a^p+r)^{p-r}$

= 5 $a^{(p+r)(p-r)}$ = 5 $a^{(p^2-r^2)}$

Performing the division, that is

$\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} }$ ← cancel $a^{(p^2-r^2)}$ on numerator/ denominator leaves

= $\frac{1}{5}$

4 0

3 years ago

PLEASE HELP !!!

Art [367]

-3•-4=12, and -3+-4=-7.
this will turn into
(x-3)(x-4)
set them up to equal zero
x-3=0, x-4=0
solve
x=3, x=4
(a)

8 0

3 years ago