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Elden [556K]
2 years ago
7

A school has 1000 students. of these, 3/4 are boys. how many of the students are boys? how many of the students are girls?

Mathematics
2 answers:
Whitepunk [10]2 years ago
8 0
750 are boys 1/4 are girls. 3/4 of 1000 is 750 and the remaining 1/4 are girls
weqwewe [10]2 years ago
6 0

Answer:

750 students are boys, 250 are girls.

Step-by-step explanation:

1/4 of 1000 is 250.

250 + 250 + 250 = 750 boys.

if 3/4 are boys, then 1/4 (the rest of the school population) are girls.

150 students are girls.

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(y-5)/2=(y+6)/3 solve
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The solution of the given equation represented in the task content can be determined by first evaluating the LCM and hence is; y= 27.

<h3>What is the solution of the equation as given in the task?</h3>

The given equation is; (y-5)/2=(y+6)/3.

Hence, by multiplying the equation by 6, we have;

3(y-5) = 2(y+6)

3y -15 = 2y +12

y = 27.

Hence, it follows that the value of y which is a solution to the equation is; y = 27.

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What is the average rate of change of f over the interval -1 on a separate sheet of paper and upload the work as a photo. Show a
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Answer:

Average rate of change for the function f(x)= x^2-x-1 over the interval -1<x<1 is -1

Step-by-step explanation:

We need to find average rate of change of f over the interval -1 < x < 1

The function given is: f(x)= x^2-x-1

The formula used to find average rate of change is:

Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}

We have, a = -1 and b = 1

Finding f(b) when b=1

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Now, finding f(a), when a= -1

f(x)=x^2-x-1\\f(-1)=(-1)^2-(-1)-1\\f(1)=1+1-1\\f(-1)=2-1\\f(-1)=1

Now, putting values and finding average rate of change

Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}\\Average\:rate\:of\:change=\frac{f(1)-f(-1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-(1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-1}{1+1}\\Average\:rate\:of\:change=\frac{-2}{2}\\Average\:rate\:of\:change=-1

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