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Elden [556K]
1 year ago
7

A school has 1000 students. of these, 3/4 are boys. how many of the students are boys? how many of the students are girls?

Mathematics
2 answers:
Whitepunk [10]1 year ago
8 0
750 are boys 1/4 are girls. 3/4 of 1000 is 750 and the remaining 1/4 are girls
weqwewe [10]1 year ago
6 0

Answer:

750 students are boys, 250 are girls.

Step-by-step explanation:

1/4 of 1000 is 250.

250 + 250 + 250 = 750 boys.

if 3/4 are boys, then 1/4 (the rest of the school population) are girls.

150 students are girls.

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Write a problem that can be solved with a bar model that shows equal groups of liters
ioda
"In Grade 2 and early in Grade 3, students learned to use bar models to solve two-step problems involving addition and subtraction. This is extended in this chapter to include multiplication and division.


<span>Both multiplication and division are based on the concept of equal groups, or the part-part-whole concept, where each equal group is one part of the whole. In Grade 2, students showed this with one long bar (the whole) divided up into equal-sized parts, or units. This unitary bar model represents situations such as basket of apples being grouped equally into bags." </span>https://www.sophia.org/tutorials/math-in-focus-chapter-9-bar-modeling-with-multipli
8 0
3 years ago
Solve for y in terms of x <br><br> -8x + 4y = -16
solniwko [45]

Answer:

y=2x-4

Step-by-step explanation:

well first you have to move the -8x to the other side where the -16 is. by doing so, the -8x will turn into a POSTIVE 8x. than your problem should look like (4y=8x-16). now that your problem is like that, you want "y" to be alone. so, you divide the 4 by every number. (so you would do 4y/4, 8x/4, and -16/4). than your final product would be: y=2x-4

4 0
3 years ago
Read 2 more answers
Why does (x-2)^2+9=0 have no real solutions?
alex41 [277]

Answer:

see explanation

Step-by-step explanation:

Given

(x - 2)² + 9 = 0 ( subtract 9 from both sides )

(x - 2)² = - 9  ( take the square root of both sides )

x - 2 = ± \sqrt{-9}

\sqrt{-9} yields no real solutions

There is no real number when multiplied by itself gives - 9

In fact the solutions to \sqrt{-9} are said to be imaginary, that is ± 3i

where i = \sqrt{-1}

If interested investigate further.

7 0
3 years ago
Two triangles can be formed with the given information. Use the Law of Sines to solve the triangles. C = 71°, a = 27, c = 26
guajiro [1.7K]

We have

SinC/ c  = Sin A / a

Sin 71/ 26 = Sin A / 27

Sin A  = 27 Sin 71 /  26  = about .982

So°

Sin-1(.982)  = A  = 79. 08°

Then angle B = 180 - 71 - 79.08 = 29.92°

And b is given by

b/sin29.92  = 26/sin 71

b = 26sin29.92/sin71 =  about 13.72

But A could also be an obtuse angle = 180 - 79.08 =  100.92°

So we have

B = 180 - 71 - 100.92 = 8.08°

And we have

b / sin 8.08  = 26/sin71

b = 26sin8.08/sin 71 = 3.865

8 0
3 years ago
Which are solutions of the equation x2 – 16 = 0? Check all that apply.
san4es73 [151]

Answer:

x=-4

x=4

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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