Answer:
The equation i.e. used to denote the population after x years is:
P(x) = 490(1 + 0.200 to the power of x
Step-by-step explanation:
This problem could be modeled with the help of a exponential function.
The exponential function is given by:
P(x) = ab to the power of x
where a is the initial value.
and b=1+r where r is the rate of increase or decrease.
Here the initial population of the animals are given by: 490
i.e. a=490
Also, the rate of increase is: 20%
i.e. r=20%
i.e. r=0.20
Hence, the population function i.e. the population of the animals after x years is:
P(x) = 490(1 + 0.200 to the power of x
Answer:
There is a 61.36% probability that a randomly selected day in November will be foggy if it is cloudy.
Step-by-step explanation:
We have these following probabilities:
An 88% probability that the day is cloudy.
An 54% probability that the day is both foggy and cloudy.
What is the probability that a randomly selected day in November will be foggy if it is cloudy?
This is the percentage of days that are cloudy and foggy divided by those that are cloudy. So:
There is a 61.36% probability that a randomly selected day in November will be foggy if it is cloudy.
Answer:
x=4, MN= 37, LM= 37, y=7.
Step-by-step explanation:
If MP is a perpendicular bisector to LN, then NP and LP are equivalent.
(Solve for y)
2y+2= 16
(Move the +2 to the right side of the equation)
2y= 14
(Divide both sides by 2 to isolate the variable)
y=7
To find x and the measure of MN and LM, solve for x in the following equation:
7x+9 = 11x-7
(Move 7x to the right side of the equation)
9 = 4x-7
(Move -7 to the right side of the equation.)
16= 4x
(Divide both sides by 4 to isolate the variable.)
4= x
Plug x back into both equations to get the measure of MN and ML
MN=7(4)+9
MN= 28+9
MN= 37
LM= 11(4)-7
LM= 44-7
LM= 37
I hope this helps!
The first angle is 76 and the second angle is 14. You can check this by doing 14+5=19 and then multiply that by 4.
Answer:
See below
Step-by-step explanation:
Two lines are parallel if they have the same slope but different y-intercepts. So the slope that can be formed given the points (-3,6) and (9,2) is (9-(-3))/(2-6)=12/-4=-3
With y=-3x+b, we need b, which can be found by plugging in either point:
2=-3(9)+b
2=-27+b
29=b
So the y-intercept therefore cannot be 29 but it can be any real number.
So the equation y=-3x+2 works, y=-3x+3, y=-3x+4, and so on....
