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2 years ago

Please look at the image

Mathematics

1 answer:

alina1380 [7]2 years ago

8 0

Answer:

$r \geqslant - 5$

Step-by-step explanation:

$50 - 4r \leqslant 70$

$- 4r \leqslant 20$

$\frac{ - 4r}{ - 4} \geqslant \frac{20}{ - 4}$

$r \geqslant - 5$

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Last summer there were 88 players at coach rodriguez basketball camp. this year there are 125% of this number of players. how ma

ludmilkaskok [199]

To determine the number of those who joined the basketball camp this year, we just have to multiply the number of those who joined last year by the decimal equivalent of the percentage given. That is,
x = 88(1.25)
x = 110
Therefore, there are a total of 110 players for this years basketball camp.

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3 years ago

Point C is twice as close to point B as it is to point A. If point A is at -30 and point B is at 30, what are two possible value

arsen [322]

different between A and B

=30-(-30)

=60

position of C from A or B

=(60÷3)×2

=40

possible value of c

=-30+40

=10

possible value of c

=30-40

=-10

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3 years ago

Read 2 more answers

Help 7th Grade math will get Brainliest

Bumek [7]

Formula : 2 x pie x radius
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2 years ago

Prove that 1/sec0-tan0= sec0+tan0

Leviafan [203]

Answer:

Step-by-step explanation:

$\text{LHS}=\frac{1}{\sec \theta-\tan \theta}\\=\frac{\sec \theta+\tan \theta}{(\sec \theta-\tan \theta)(\sec \theta+\tan \theta)}\\=\frac{\sec \theta+\tan \theta}{\sec^{2} \theta-\tan^{2} \theta}\\=\frac{\sec \theta+\tan \theta}{1}\\=\sec \theta+\tan \theta\\=\text{RHS}$

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1 year ago

Write a coordinate proof to prove that the segment that joins the vertex angle of an isosceles triangle to the midpoint of its b

Natalija [7]

Answer:

Slope of the base segment line is zero, hence base segment is horizontal

Slope of the segment that joins the vertex angle to the midpoint of its base is undefined hence the line is vertical

Therefore, angle between base segment line and the segment line from the vertex angle to the midpoint is perpendicular

Therefore, the segment that joins the vertex angle to an isosceles triangle to the midpoint of its base is perpendicular to the base

Step-by-step explanation:

Here we prove the required relation as follows;

Let the isosceles be ABC

The coordinates of the points are

C = (0, 0) (Vertex)

A = (-a, b)

C = (a, b)

P = (0, b) (Midpoint of base)

Therefore, the gradient or slope of the base AC is presented as follows;

$Slope, m \, of \. base, \, AC= \frac{dy}{dx} = \frac{b - b}{a - (-a)} = \frac{0}{2\cdot a} = 0$

Hence, segment AC is vertical

$Slope, m \, of \, segment \ CP \, joining \, vertex, \, to \, midpoint, P, on \,AC = \frac{0 - b}{0 - 0} = \frac{-b}{0} = Undifined.$

Hence, segment CP is vertical

Therefore, the segment that joins the vertex angle to an isosceles triangle to the midpoint of its base is perpendicular to the base.

6 0

3 years ago