Answer:
p(t) = 0.19e0.10t
=>p'(t) = 0.19e0.10t (0.10*1)
=>p'(t) = 0.019e0.10t
t = 0 represents 1994
for 2002, t=2002-1994 =8
in 2002
average price =p(8)
=>average price = 0.19e0.10*8
=>average price =0.422853... million
rate of increase =p'(8)
=>rate of increase = 0.019e0.10*8
=>rate of increase =0.0422853... million per year
p(8)=$ 0.42 million
p'(8)=$ 0.042 million per year
Make them count jelly beans.
The "Property<span> of </span>Zero" of Multiplication <span>shows that the product of </span>zero<span> and any number is </span>zero<span>.
</span>
Here is one example:
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5 x 0 = 0 .
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{"Five times zero equals zero."}.
{"Five multiplied by zero equals zero".}.
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Answer:
59 to 66
Step-by-step explanation:
Mean test scores = u = 74.2
Standard Deviation =
= 9.6
According to the given data, following is the range of grades:
Grade A: 85% to 100%
Grade B: 55% to 85%
Grade C: 19% to 55%
Grade D: 6% to 19%
Grade F: 0% to 6%
So, the grade D will be given to the students from 6% to 19% scores. We can convert these percentages to numerical limits using the z scores. First we need to to identify the corresponding z scores of these limits.
6% to 19% in decimal form would be 0.06 to 0.19. Corresponding z score for 0.06 is -1.56 and that for 0.19 is -0.88 (From the z table)
The formula for z score is:

For z = -1.56, we get:

For z = -0.88, we get:

Therefore, a numerical limits for a D grade would be from 59 to 66 (rounded to nearest whole numbers)
Answer: SAS
Step-by-step explanation: