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andrezito [222]
3 years ago
7

Giving away 40 points

Mathematics
2 answers:
Sladkaya [172]3 years ago
8 0

Answer:

im pretty sure its 20.4

Step-by-step explanation:

soery if im wrong

Lana71 [14]3 years ago
4 0

Answer:

20.4

Step-by-step explanation:

im not sure tho

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Panel of judges was asked to judge the quality of different kinds of potato chips. The scatterplot and regression line below sho
nika2105 [10]

Answer:

D

Step-by-step explanation:

the slope begins at $1

6 0
3 years ago
-(m-6)=3m+14 what is m
natta225 [31]
The answer is
- m + 6 = 3m + 14
- 4m = 8
m =  - 2
8 0
2 years ago
(2 x 10*)(5.7 x 10°) ^x =​
sineoko [7]

Answer:

20 x 57^x / 10^x

Step-by-step explanation:

8 0
3 years ago
the area of a rectangle is 90 in2^. the ratio of the length to the width is 5:2. find the length and the width
-BARSIC- [3]

Length and width of rectangle is 15 inches and 6 inches respectively

<h3><u>Solution:</u></h3>

Given that area of a rectangle is 90 square inch

Ratio of length to the width = 5: 2.

Need to determine length and width of rectangle.  

As ratio of length to the width is 5 : 2

Lets assume length of rectangle = 5x inches and width of rectangle = 2x inches.

<em><u>The formula for area of rectangle is given as:</u></em>

\text { Area of rectangle }=\text { length of rectangle } \times \text { width of rectangle}

Substituting the given value of area of rectangle and assumed value of length and width of rectangle we get:

\begin{array}{l}{90=5 x \times 2 x} \\\\ {=>90=10 x^{2}}\end{array}

On solving the above expression for x we get

\begin{array}{l}{=>\frac{90}{10}=x^{2}} \\\\ {=>x^{2}=9} \\\\ {=>x=\sqrt{9}=3}\end{array}

\begin{array}{l}{\text { Length of rectangle }=5 \times x=5 \times 3=15 \text { inches }} \\\\ {\text { Width of rectangle }=2 \times} x=2 \times} 3=6 \text { inches }}\end{array}

Hence length and width of rectangle is 15 inches and 6 inches.

4 0
3 years ago
Let G be a connnectde graph with n vertices and m edges. supposed also that m = n. prove that G contains exactly one cycle
ElenaW [278]

Answer:

Contradiction

Step-by-step explanation:

Suppose that G has more than one cycle and let C be one of the cycles of G, if we remove one of the edges of C from G, then by our supposition the new graph G' would have a cycle. However, the number of edges of G' is equal to m-1=n-1 and G' has the same vertices of G, which means that n is the number of vertices of G. Therefore, the number of edges of G' is equal to the number of vertices of G' minus 1, which tells us that G' is a tree (it has no cycles), and so we get a contradiction.

7 0
3 years ago
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