Answer:
<h2>
$26.25</h2>
<em><u>Solving steps:</u></em>
<em>Question:</em> <u>Sam had some money in his pocket, and he found another $6. 50 in his dresser drawer. He then had a total of $19. 75. Let p represent the amount of money Sam had in his pocket. Which equation can you use to find the amount of money Sam had in his pocket? How much money did Sam have in his pocket?.</u>
<em>Find: </em><em> </em><u>How much money did Sam have in his pocket?.</u>
<em>Solution:</em><em> </em>Let the equation be
<h3><em>=> P = T </em><em>+</em><em>F</em></h3>
<u>p represent amount of money</u>
<u>p represent amount of moneyt represent total</u>
<u>p represent amount of moneyt represent totalf represent money found</u>
<h3>
<em>=> P = T </em><em>+</em><em> </em><em>F</em></h3>
<u>insert the values</u>
<h3><em>=> P = $19.75 </em><em>+</em><em> </em><em>$6.50</em></h3>
add<u> 19.75 from 6.50 </u>
<h3><em>=> P = </em><em> </em><em>26.25</em></h3>
<em><u>THEREFORE THE AMOUNT OF MONEY </u></em><em><u>SAM</u></em><em><u> HAVE IN HIS POCKET</u></em><em><u> IS ABOUT</u></em><em><u> </u></em><em><u> </u></em><em><u>$</u></em><em><u>26.25</u></em>
Annual interest is P*r^t, r is 0.05 here, t is 9/12=3/4=0.75
P*0.05^0.75=120
use your calculaor: P= 120÷ (0.05)^0.75=1135
so he invested about 1135 dollars
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<h3>
Answer: 60</h3>
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Explanation:
Multiply the two values to get 4*15 = 60
Then divide by the GCF 1 to get 60/1 = 60. The GCF being 1 means the result hasn't changed.
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Another example would be: "Find the LCM of 6 and 8". We would first do 6*8 = 48, then divide by the GCF 2 to get 48/2 = 24. The LCM of 6 and 8 is 24.
Answer:
Good luck :)
Step-by-step explanation:
S=2πrh+2πr ²
subtract 2πr ² from each side
S -2πr ² = 2πrh
divide by 2πr from each side
(S -2πr ² )/ 2πr = h
