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natta225 [31]
3 years ago
8

Three friends were comparing scores on a social studies test Henry got a score of 7/8 Christian got a score of 75% in McKenzie g

ot a score of 0.625 who got the highest score on the test explain
Mathematics
1 answer:
dolphi86 [110]3 years ago
6 0
Henry.7/8 is equivalent to 87.5%
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Step-by-step explanation:

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What are the new coordinates of (6, -1) if it is shifted 7 units to the left
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The answer is -1


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3 years ago
What is 1/3 multiply 2/4
Greeley [361]

Answer:

1/3 * 2/4 = 1/3 * 1/2 = (1*1)/(3*2) = 1/6

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3 years ago
Read 2 more answers
A) Write each expression in expanded form. B) Then calculate the value of the
Tatiana [17]

A) (3)² = 3 × 3 and 10(8)² = 10 × 8 × 8

B) (3)² = 9 and 10(8)² = 640

For any number x, the square of the number denoted by (x)² is equal to 2 times x multiplied by itself or x*x.

Here, we are given two expressions- (3)² and 10(8)²

we need to write both of them in expanded form and then write their values.

Expanded form of (3)² is 3 × 3

The value of the expression (3)² will be-

(3)² = 3 × 3 = 9

Similarly, expanded form of 10(8)² is 10 × 8 × 8

The value of the expression 10(8)² will be-

10(8)² = 10 × 8 × 8 = 640

Learn more about expanded form here-

https://brainly.in/question/19612773

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8 0
2 years ago
A manufacturer has been selling 1000 flat-screen TVs a week at $500 each. A market survey indicates that for A manufacturer has
luda_lava [24]

Answer:

a) Demand function: q=6000-10\cdot p

b) The rebate should be of $200, so the sale price becomes $300 per unit.

c) The rebate should be of $150, so the sale price becomes $350 per unit.

Step-by-step explanation:

a) In this case, we have a known point of the demand function (1000 units sold at $500), and the slope of a linear function (increase by 100 units fora decrease in $10).

We can express the demand function (linear) as:

q=b+m\cdot p

To calculate the slope m, we use:

m=\Delta q/\Delta p=(+100)/(-10)=-10

To calculate b, we use the known point and the calculated slope:

q=b+m\cdot p\\\\b=q-m\cdot p=1000-(-10)\cdot (500)=1000+5000=6000

Then the demand function is:

q=6000-10\cdot p

b) The revenue can be expressed as:

R=q\cdot p = (6000-10p)\cdot p=6000p-10p^2

To maximize, we can derive and equal to zero

dR/dp=6000-2*10p=0\\\\20p=6000\\\\p=300

The rebate should be of $200, so the sale price becomes $300 per unit.

c) If we take into account the cost, we have that

R=q\cdot p-C=(6000p-10p^2)-(68000+100q)\\\\R=(6000p-10p^2)-(68000+100(6000-10p))\\\\R=6000p-10p^2-(68000+600000-1000p)\\\\R=-10p^2+7000p-668000

To maximize, we can derive and equal to zero

dR/dp=-20p+7000=0\\\\p=7000/20=350

The rebate should be of $150, so the sale price becomes $350 per unit.

5 0
3 years ago
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