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Phoenix [80]
3 years ago
10

I'LL GIVE YOU 20 POINTS AND BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
6 0

Answer:

I can see how this is confusing, because of -2, but the slope is decreasing, so the question wouldn't say:

-3/5x - -2

This happens to turn the -2 into a regular 2 with an addition (+) sign.

and since the graph has an input of 5 but an output of -3, the equation would be:

y = -3/5x + 2

Harlamova29_29 [7]3 years ago
3 0
It is the 5th Blue one:) We know this because the y-intercept is -2.
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write the equation of the line passing through the points (-2, 3) and (-1,-2) in slope intercept and point slope form
cestrela7 [59]

<u>in</u><u> </u><u>slope</u><u> </u><u>in</u><u>t</u>ercept

y = -5x - 7

point slope form

y + 5x - 7 =0

8 0
3 years ago
Please help quick !
love history [14]

Answer:

10 A. Quadrent 2

10 B. Quadrent 3

Step-by-step explanation:

Image

5 0
3 years ago
From 42 acres to 72 acres (round to the nearest percent
guajiro [1.7K]

Answer:

42 acres to 72 acres, there is an increase of 30 acres

percentage wise

72-42=30

30/72=.4166...

therefore there is also a 41.6% increase

Step-by-step explanation:

71.42 Percentage change:×100%

Now, the change is given from 42 acres to 72 acres, therefore

Change= 72-42=30

⇒Percentage change= ×100%

                                   = 71.42

8 0
3 years ago
An artist wishes to make a sign in the shape of an isosceles triangle as shown. find the area
Katarina [22]

Answer:

Step-by-step explanation:

Drop an angle bisector from angle C until it intersects AB. Because of the symmetry of the triangles created, you will form two small right angle congruent triangles. Call the point of intersection with AB = D. In other words the bisector of <C is CD.

CB = AC                          Isosceles triangle

CD / CB = Sin(38.5)        

  CD=?

  CB = 35

CD / 35 = Sin(38.5)      Multiply both sides by 35

CD = 35 * sin(38.5)

CD = 21.79

BD/CB  =  Cos(38.5)

BD = CB* Cos(38.5)

BD = 35 * Cos (38.5)

BD = 27.39

Area = CD * BA/2

BA/2 = DB

Area = CD * BD

Area = 21.79 * 27.39

Area = 596.9

3 0
3 years ago
Verify that the conclusion of Clairaut’s Theorem holds, that is, uxy = uyx, u=tan(2x+3y)
choli [55]

Answer: Hello mate!

Clairaut’s Theorem says that if you have a function f(x,y) that have defined and continuous second partial derivates in (ai, bj) ∈ A

for all the elements in A, the, for all the elements on A you get:

\frac{d^{2}f }{dxdy}(ai,bj) = \frac{d^{2}f }{dydx}(ai,bj)

This says that is the same taking first a partial derivate with respect to x and then a partial derivate with respect to y, that taking first the partial derivate with respect to y and after that the one with respect to x.

Now our function is u(x,y) = tan (2x + 3y), and want to verify the theorem for this, so lets see the partial derivates of u. For the derivates you could use tables, for example, using that:

\frac{d(tan(x))}{dx} = 1/cos(x)^{2} = sec(x)^{2}

\frac{du}{dx}  =  \frac{2}{cos^{2}(2x + 3y)} = 2sec(2x + 3y)^{2}

and now lets derivate this with respect to y.

using that \frac{d(sec(x))}{dx}= sec(x)*tan(x)

\frac{du}{dxdy} = \frac{d(2*sec(2x + 3y)^{2} )}{dy}  = 2*2sec(2x + 3y)*sec(2x + 3y)*tan(2x + 3y)*3 = 12sec(2x + 3y)^{2}tan(2x + 3y)

Now if we first derivate by y, we get:

\frac{du}{dy}  =  \frac{3}{cos^{2}(2x + 3y)} = 3sec(2x + 3y)^{2}

and now we derivate by x:

\frac{du}{dydx} = \frac{d(3*sec(2x + 3y)^{2} )}{dy}  = 3*2sec(2x + 3y)*sec(2x + 3y)*tan(2x + 3y)*2 = 12sec(2x + 3y)^{2}tan(2x + 3y)

the mixed partial derivates are equal :)

7 0
3 years ago
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