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photoshop1234 [79]
3 years ago
15

Partial-Year Depreciation Sandblasting equipment acquired at a cost of $42,000 has an estimated residual value of $6,000 and an

estimated useful life of 10 years. It was placed in service on October 1 of the current fiscal year, which ends on December 31, 20Y5. a. Determine the depreciation for 20Y5 and for 20Y6 by the straight-line method. Depreciation 20Y5 $fill in the blank 1 20Y6 $fill in the blank 2 b. Determine the depreciation for 20Y5 and for 20Y6 by the double-declining-balance method.
Business
1 answer:
Deffense [45]3 years ago
4 0

Answer:

A. Depreciation expense in 20Y5 = $900

Depreciation expense in 20Y6 = $3,600

B. Depreciation expense in 20Y5 = $2800

Depreciation expense in 20Y6 =$7840

Explanation:

Straight line depreciation expense = (Cost of asset - Salvage value) / useful life

($42,000 - $6,000) / 10 = $3,600

The depreciation expense would be $3600 each year except in 20Y5. when the equipment was used from October to December which is 3 months

Depreciation expense in 20Y5 = 3/12 x $3600 = $900

Depreciation expense using the double declining method = Depreciation factor x cost of the asset

Depreciation factor = 2 x (1/useful life)  = 2/10 = 0.2

Depreciation expense in 20Y5 = 0.2 x $42,000 = $8,400

But the equipment was only used for 3 months, so we would divide the figure above by 3

$8400 / 3 = $2800

Depreciation expense in 20Y5 = $2800

Depreciation expense in 20Y6 = book value in the beginning of 20Y6 x depreciation expense

Book value = cost of the asset - depreciation expense in 20Y5

$42,000 - $2800 = $39,200

Depreciation expense in 20Y6 = $39,200 x 0.2 = $7840

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Yakvenalex [24]

Answer:

It is cheaper to make the part in house.

Explanation:

Giving the following information:

Harrison Enterprises currently produces 8,000 units of part B13.

Current unit costs for part B13 are as follows:

Direct materials $12

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Total $45

If Harrison decides to buy part B13, 50% of the administrative costs would be avoided.

To calculate whether it is better to make the par in-house or buy, we need to determine which costs are unavoidable.

Unavoidable costs:

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Administrative costs= 5

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Now, we can calculate the unitary cost of making the product in-house:

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3 years ago
A manufacturing operation consists of 10 operations. However, five machining operations must be completed before any of the rema
Anit [1.1K]

Answer:

The answer is: 14,400 different production sequences are possible

Explanation:

For this calculation I will assume that the first 5 operations can be made in any order, as well as the last 5.

For the first set of machining operations, since they can go in any order, you choose one operation and then you have 4 operations left, then you choose another operation and you have 3 operations left, then you choose another operation and you have 2 operations left, you choose another option and you have only 1 operation left.  This process can be expressed by the following equation: 5 x 4 x 3 x 2 x 1 = 120 possible different combinations. Mathematically it can also be expressed as 5! = 120

The same for the last 5 assembly operations, you have 5 x 4 x 3 x 2 x 1 = 120 possible different combinations.

So to get the total possible combinations of all the process, we just multiply 120 x 120 = 14,000 or 5! x 5! = 14,400

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