Add, -11.5x and move it over to 8.5x
Then, subtract them together and you get 20x + 51.86 = 51.76
And you move (subtract) 51. 86 over to 51.76, subtract that and you get 20x = -0.1
Divide, and your answer is -200
Answer:
80 pages
Step-by-step explanation:
x = number of pages of articles
x = 110 - (23 + 14/2)
x = 110 - (23 + 7)
x = 110 - 30
x = 80
Answer:
Option 4
Step-by-step explanation:
The volume of a cylinder is going to be the area of the base (which is a circle) times the height. if you have cylindrical mug, then you can use the base area×height relationship, but it won't be exact because some of the volume is going to be used for the walls of the mug itself.
Anyways:
Volume = Base Area × Height
•Base Area -> Circle = π×radius²
•Height is given as 7in.
Volume = π×(6.2in)² × 7in = 845.33975...
Volume is in units cubed (the 3rd power) which is where the in³ is from. Your closest option here looks to be the 4th choice.



with that template in mind, let's see

so B went form 1 on f(x), down to 0.5 or 1/2 on g(x)
B = 1/2, thus the graph is stretched by twice as much.
If you plot the points you will find you have to use the distance formula. Pick out 2 pairs label them (x1,y1) (x2,y2) then plug it into the distance formula. The repeat for the other sides. So you should get (2,5) (4,3) plug into distance formula what is get it distance between those two points, then (4,3) (-2,-1) plug into distance formula to get an answer, lastly (-2,-1) (2,5) plug in. Now you have three answers add all together and here is your perimeter of a triangle.