AB = √(5-0)^2 + (4-0)^2 = √25+16 = √41
BC = √(0-5)^2 + (8-4)^2 = √25+16 = √41
CD = √(-5 - 0)^2 + (4-8)^2 = √25+16 = √41
AD = √(-5-0)^2 + (4-0)^2 = √25+16 = √41
All the sides are equal so it is either a square or a rhombus.
The distance from A to C on the x axis is: 8-0 = 8 units.
The distance from B to D on the Y axis is: 5 - - 5 = 10 units.
Because the two distances are not the same, it is not a square.
The answer is 4. AB=BC ; therefore, ABCD is a rhombus.
All real numbers greater than -3
Answer:
it will be 3/4
Step-by-step explanation:
that what i thank it is.
A: no solution!
first, simplify each side of the equation.
3x + 5 - 10x simplifies to -7x + 5.
8 - 7x - 12 simplifies to -7x - 4.
then, add +7x on both sides of the equation to get the variable alone. if you add 7x to each side, you get left with 0.
so, that leaves 5 = -4 which is not true. so, that means there is no solution.
Step-by-step explanation:
the question is not correct
edit it and I will answer u in comments
