All categories

3 years ago

What is the answer to this ?

Mathematics

1 answer:

erma4kov [3.2K]3 years ago

8 0

Answer:

B shows a translation of three units to the right

You might be interested in

The height of one square pyramid is 12 m. A similar pyramid has a height of 6 m. The volume of the larger pyramid is 400 m3. Det

tatiyna

$\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\
$

$\bf \cfrac{smaller}{larger}\qquad \cfrac{\stackrel{height}{6}}{\stackrel{height}{12}}\implies \cfrac{1}{2}\impliedby \textit{scale factor of the pyramids}\\\\
-------------------------------\\\\
\cfrac{smaller}{larger}\qquad \cfrac{h}{h}=\cfrac{\sqrt{base}}{\sqrt{base}}\implies \cfrac{1}{2}=\sqrt{\cfrac{base}{base}}\implies \left( \cfrac{1}{2} \right)^2=\cfrac{base}{base}
\\\\\\
\cfrac{1^2}{2^2}=\cfrac{base}{base}\implies \cfrac{1}{4}=\cfrac{base}{base}\\\\
-------------------------------\\\\$

$\bf \cfrac{smaller}{larger}\qquad \cfrac{h}{h}=\cfrac{\sqrt[3]{volume}}{\sqrt[3]{volume}}\implies \cfrac{1}{2}=\sqrt[3]{\cfrac{volume}{volume}}
\\\\\\
\left( \cfrac{1}{2} \right)^3=\cfrac{volume}{volume}
\implies 
\cfrac{1^3}{2^3}=\cfrac{volume}{volume}\implies \cfrac{1}{8}=\cfrac{volume}{volume}\\\\
-------------------------------\\\\
\cfrac{smaller}{larger}\qquad \cfrac{1}{8}=\cfrac{\stackrel{volume}{v}}{\stackrel{volume}{400}}\implies \cfrac{1\cdot 400}{8}=v$

7 0

3 years ago

What is the answer to <br> 3/5x10=

Ulleksa [173]

3/5=.6

.6*10=6

so 6 is the answers

5 0

2 years ago

Read 2 more answers

WILL GIVE BRAINLIEST.

Elena L [17]

Answer:

$\tan(\theta) =$ undefined

Step-by-step explanation:

Given

$\sin(\theta) = -1$

Required

Determine $\tan(\theta)$

We know that:

$\sin^2(\theta) + \cos^2(\theta) = 1$

This gives:

$(-1)^2 + \cos^2(\theta) = 1$

$1 + \cos^2(\theta) = 1$

Collect like terms

$\cos^2(\theta) = 1 -1$

$\cos^2(\theta) = 0$

Take square roots

$\cos(\theta) = \sqrt 0$

$\cos(\theta) = 0$

By tan identity

$\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}$

$\tan(\theta) = \frac{-1}{0}$

$\tan(\theta) =$ undefined

6 0

3 years ago

How is the vertex related to the maximum or minimum of a parabola?

USPshnik [31]

Answer:

Vertical parabolas give an important piece of information: When the parabola opens up, the vertex is the lowest point on the graph — called the minimum, or min. When the parabola opens down, the vertex is the highest point on the graph — called the maximum, or max.

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Seven times one number is half of another number... please put in equation form

allsm [11]

7 x 1 =1/2 of another number heres the answe

4 0

3 years ago

Read 2 more answers