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Klio2033 [76]
3 years ago
13

What is the answer to this ?

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
8 0

Answer:

B shows a translation of three units to the right

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The height of one square pyramid is 12 m. A similar pyramid has a height of 6 m. The volume of the larger pyramid is 400 m3. Det
tatiyna
\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\


\bf \cfrac{smaller}{larger}\qquad \cfrac{\stackrel{height}{6}}{\stackrel{height}{12}}\implies \cfrac{1}{2}\impliedby \textit{scale factor of the pyramids}\\\\
-------------------------------\\\\
\cfrac{smaller}{larger}\qquad \cfrac{h}{h}=\cfrac{\sqrt{base}}{\sqrt{base}}\implies \cfrac{1}{2}=\sqrt{\cfrac{base}{base}}\implies \left( \cfrac{1}{2} \right)^2=\cfrac{base}{base}
\\\\\\
\cfrac{1^2}{2^2}=\cfrac{base}{base}\implies \cfrac{1}{4}=\cfrac{base}{base}\\\\
-------------------------------\\\\

\bf \cfrac{smaller}{larger}\qquad \cfrac{h}{h}=\cfrac{\sqrt[3]{volume}}{\sqrt[3]{volume}}\implies \cfrac{1}{2}=\sqrt[3]{\cfrac{volume}{volume}}
\\\\\\
\left( \cfrac{1}{2} \right)^3=\cfrac{volume}{volume}
\implies 
\cfrac{1^3}{2^3}=\cfrac{volume}{volume}\implies \cfrac{1}{8}=\cfrac{volume}{volume}\\\\
-------------------------------\\\\
\cfrac{smaller}{larger}\qquad \cfrac{1}{8}=\cfrac{\stackrel{volume}{v}}{\stackrel{volume}{400}}\implies \cfrac{1\cdot 400}{8}=v
7 0
3 years ago
What is the answer to <br> 3/5x10=
Ulleksa [173]
3/5=.6

.6*10=6

so 6 is the answers
5 0
2 years ago
Read 2 more answers
WILL GIVE BRAINLIEST.
Elena L [17]

Answer:

\tan(\theta) = undefined

Step-by-step explanation:

Given

\sin(\theta) = -1

Required

Determine \tan(\theta)

We know that:

\sin^2(\theta) + \cos^2(\theta) = 1

This gives:

(-1)^2 + \cos^2(\theta) = 1

1 + \cos^2(\theta) = 1

Collect like terms

\cos^2(\theta) = 1 -1

\cos^2(\theta) = 0

Take square roots

\cos(\theta) = \sqrt 0

\cos(\theta) = 0

By tan identity

\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}

\tan(\theta) = \frac{-1}{0}

\tan(\theta) = undefined

6 0
3 years ago
How is the vertex related to the maximum or minimum of a parabola?
USPshnik [31]

Answer:

Vertical parabolas give an important piece of information: When the parabola opens up, the vertex is the lowest point on the graph — called the minimum, or min. When the parabola opens down, the vertex is the highest point on the graph — called the maximum, or max.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Seven times one number is half of another number... please put in equation form
allsm [11]
7 x 1 =1/2 of another number heres the answe
4 0
3 years ago
Read 2 more answers
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