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zmey [24]
3 years ago
5

Bob owned 25 pairs of shoes in January, but then he sold a bunch and now owns 12. What is the percent decrease?

Mathematics
1 answer:
polet [3.4K]3 years ago
5 0
52% decrease hope this helps!!
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How do you solve rectangular prisms.
LiRa [457]
What is the question ? What do yis u want to find ? The area, volume surface area...?! Be more specific , then I will be able to help you :)
4 0
3 years ago
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Solve the equation for x 6x + 1 - 4x = 2+ x + 4
Nina [5.8K]
First simplify all of the numbers with common variables (or those without)

6x - 4x + 1 = 2 + x + 4

2x + 1 = x + 6

subtract x from both sides to move x to one side

2x (-x) + 1 = x (-x) + 6

x + 1 = 6

subtract 1 from both sides to isolate the x

x + 1 (-1) = 6 (-1)

x = 6 - 1

x = 5

5 is your answer for x

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4 0
3 years ago
Please help ASAP 12 points
Roman55 [17]

Answer:

they are opposites

Step-by-step explanation:

7 0
4 years ago
Can someone explain how to do #3?
dsp73

\displaysyle (\sqrt 2)^{3}=(2^{\frac{1}{2}})^3=2^{\frac{1}{2} \cdot 3}=2^{\frac{3}{2}}=\sqrt {2^3}=\sqrt 8

√8 is between 2 and 3, because 2²=4<8, but 3²=9>8. Also, our value is closer to 3 than to 2, so it is more than 2.5 and we have C and D options left.

Among these two numbers we find the one which is closer to √8.

C. 27=√729 ⇒ 2.7=√7.29

D. 28=√784 ⇒ <u>2.8=√7.84</u>

Hence our answer is D) 2.8

5 0
4 years ago
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Suppose x and y are nonzero vectors in an inner product space. Show that x and y are orthogonal if and only if ||x+y|| = ||x-y||
harkovskaia [24]

Answer:

Step-by-step explanation:

Suppose x and y are nonzero vectors in an inner product space.

Let us assume that x and y are orthogonal

i.e. innter product is 0.

This implies dot product of x and y is 0

Then x.y =0

i.e. x^2+y^2 +2x.y = x^2+y^2-2x.y\\||x+y||=||x-y||

Proved

Converse part:

Let ||x+y||=||x-y||

Square also would be equal

||x+y||^2=||x-y||^2\\||x||^2+||y||^2+2x,t=||x||^2+||y||^2-2x.y\\x.y =0

Hence inner product of x and y is 0

7 0
3 years ago
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