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Kipish [7]
2 years ago
12

In the year 2008, a person bought a new car for $26500. For each consecutive year

Mathematics
1 answer:
DanielleElmas [232]2 years ago
6 0

Answer:

$20500

Step-by-step explanation:

26500-(.12*26500)=23320 For 1 year

23320-(.12*23320)=$20521.60 For 2 years

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It seems to you that fewer than half of people who are registered voters in the City of Madison do in fact vote when there is an
Ad libitum [116K]

Answer:

a) Going to public places like restaurants, parks, theaters, etc in Madison and asking voters.

b) The 80% CI to estimate the true proportion of registered voters in the City of Madison who vote in non-presidential elections is (0.5533, 0.6667).

c) We are 80% sure that our confidence interval contains the true proportion of registered voters in the City of Madison who vote in non-presidential elections.

d) The lower limit of the interval is higher than 0.5. This means that it does seem that MORE than half of registered voters in the City of Madison vote in non-presidential elections.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

(a) How might a simple random sample have been gathered?

Going to public places like restaurants, parks, theaters, etc in Madison and asking voters.

(b) Construct an 80% CI to estimate the true proportion of registered voters in the City of Madison who vote in non-presidential elections.

You take an SRS of 200 registered voters in the City of Madison, and discover that 122 of them voted in the last non-presidential election. This means that n = 200, \pi = \frac{122}{200} = 0.61.

We want to build an 80% CI, so \alpha = 0.20, z is the value of Z that has a pvalue of 1 - \frac{0.20}{2} = 0.90[tex], so [tex]z = 1.645.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{200}} = 0.61 - 1.645\sqrt{\frac{0.61*0.39}{200}} = 0.5533

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{200}} = 0.61 + 1.645\sqrt{\frac{0.61*0.39}{200}} = 0.6667

The 80% CI to estimate the true proportion of registered voters in the City of Madison who vote in non-presidential elections is (0.5533, 0.6667).

(c) Interpret the interval you created in part (b).

We are 80% sure that our confidence interval contains the true proportion of registered voters in the City of Madison who vote in non-presidential elections.

(d) Based on your CI, does it seem that fewer than half of registered voters in the City of Madison vote in non-presidential elections? Explain.

The lower limit of the interval is higher than 0.5. This means that it does seem that MORE than half of registered voters in the City of Madison vote in non-presidential elections.

4 0
3 years ago
Help I need to know which one
Rufina [12.5K]

The best answer would be D

Because Rotational symmetry is a symmetric shape that can be rotated but appear the same.


7 0
3 years ago
A salesperson gets a 3% commission on the sale of a copy machine. What is his commission on a copy machine that costs $4,950.00?
kondor19780726 [428]
4,950×3=1650
1650÷100=16.5
his commission is $16.5
7 0
3 years ago
Will mark branliest answer if gotten right!!!!!
Crank

Answer:

it is 4

Step-by-step explanation:

i will do this some other time

7 0
3 years ago
What is the percent of change if 38 is decreased to 25? round to the nearest whole number
motikmotik

Answer:

7.89474% decrease

Step-by-step explanation:

Solution:

Calculate percentage change

from V1 = 38 to V2 = 35

(V2−V1)|V1|×100

=(35−38)|38|×100

=−338×100

=−0.0789474×100

=−7.89474%change

=7.89474%decrease

7 0
2 years ago
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