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nirvana33 [79]
3 years ago
15

HELP ME PLZZ I NEED HELP WITH THIS

Mathematics
1 answer:
Ulleksa [173]3 years ago
8 0

Answer:

25 + 11 hope this helps

Step-by-step explanation:

answer is the third one

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In one day, a family in a car rode for 2 hours, stopped for 3 hours, and then rode for another 5 hours. During the day, the fami
Stells [14]
They rode for 7 hours and traveled 400 kilometers.

Divide:

400 / 7 = 57.14

Answer = 57.14

Hope this helped☺☺
5 0
3 years ago
In a pile of 55 coins made of nickels and dimes totaling $3.90 how many of each coin are there
tigry1 [53]
There are 5 pennies in a nickel, and 10 pennies in a dime.  Now in $3.90 there are 390 pennies.

n = number of nickels in the pile

d = number of dimes in the pile

we know the pile has 55 coins, therefore whatever "n" and "d" are, we know that n + d = 55.

now, "n" is how many nickel coins are there, how many pennies is it in total?  well, 5 pennies to a nickel, for "n" nickels, will then be 5(n) or 5n.

and "d" is how many dime coins are there, so therefore in "d" coins, there are 10(d) pennies, or 10d.

we also know the total amount of pennies is 390, therefore 5n + 10d = 390.

\bf \begin{cases}
n+d=55\implies \boxed{n}=55-d\\
5n+10d=390\\
-------------\\
5\left(\boxed{55-d}  \right)+10d=390
\end{cases}
\\\\\\
275-5d+10d=390\implies 5d=115\implies d=\cfrac{115}{5}\implies d=23

how many nickel coins are there anyway?  well, n = 55 - d.
8 0
3 years ago
I need help with this question. IT IS NOT MULTICHOICE. again, IT ISNT MULTICHOICE. (brainliest, 12 pts)
Rasek [7]

Answer:

Part A) The given enrollment numbers as a pair of points are (0,900) and (3,1,500)

Part B) The slope of the line is m=200\ \frac{students}{year} (see the explanation)

Part C) P=200t+900

Part D) P=2,500\ students

Step-by-step explanation:

Part A) Write the given enrollment numbers as a pair of points in the form (t,P)

Let

t ----> the number of years since 2009 (independent variable or input value)

P ---->the high school's student enrollment (dependent variable or output value)

we know that

For t=0 (year 2009) ----> P=900 students

so

The first ordered pair is (0,900)

For t=2012-2009=3 years ----> P=1,500 students

so

The second ordered pair is (3,1,500)

therefore

The given enrollment numbers as a pair of points are (0,900) and (3,1,500)

Part B) Find the slope of the line passing though the pair of points

we know that

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

we have

(0,900) and (3,1,500)

substitute the values

m=\frac{1,500-900}{3-0}

m=\frac{600}{3}

m=200\ \frac{students}{year}

That means that the high school's student enrollment increase at rate of 200 students by year since 2009

Part C) Write an equation that relates the high school's student enrollment, P, to the number of years since 2009, t

we know that

The equation of a line in slope intercept form is equal to

P=mt+b

where

m is the slope

b is the P-intercept

In this problem we have

m=200

b=900 ---> represent the initial value ( value of P when the value of t is equal to zero)

substitute

P=200t+900

Part D) Predict the high school's enrollment in 2017

For t=2017-2009=8 years

substitute the value of t in the linear equation

P=200(8)+900

P=2,500\ students

3 0
3 years ago
Chris is standing near a tree. Chris is six feet tall and his shadow is two feet long.
Keith_Richards [23]

Answer:

Step-by-step explanation:

t/8=6/2

t=48/2

t=24 ft

7 0
3 years ago
On a coordinate plane, a line goes from point (negative 3, negative 2) to (2, 4). The distance between the two points pictured i
Mnenie [13.5K]

Answer:

n =

Step-by-step explanation:

Although the image is not shown, I imagine that what they are asking (n) is the length of the segment that joins both points. If that is the case, we first proceed to identify each of the given points with the general form of coordinate pairs on the plane. For example, we identify:

(-3,-2) = (x_1,y_1)\\(2,4)=(x_2,y_2)\\

Now we use the distance formula replacing the general coordinates by the given values as follows:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\d=\sqrt{(2-(-3))^2+(4-(-2))^2}\\d=\sqrt{5^2+6^2} \\d=\sqrt{25+36} \\d=\sqrt{61}

7 0
3 years ago
Read 2 more answers
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