Answer:
Oxygen passes quickly through this air-blood barrier into the blood in the capillaries. Similarly, carbon dioxide passes from the blood into the alveoli and is then exhaled.
Explanation:
Answer:
Macromolecules are transported from one space to another through a process of transcytosis or transcellular transport. It consists of a series of steps that will allow the mobility of macromolecules from one extracellular space to another, through the cellular menbrain, through a vesicle formation process. These vesicles maintain a certain load inside. The processes that are generated for the transcytosis process are those of endocytosis and exocytosis.
Answer:
Okay
Explanation:
Human topoisomerase I plays an important role in removing positive DNA supercoils that accumulate ahead of replication forks. It also is the target for camptothecin-based anticancer drugs that act by increasing levels of topoisomerase I-mediated DNA scission. Evidence suggests that cleavage events most likely to generate permanent genomic damage are those that occur ahead of DNA tracking systems. Therefore, it is important to characterize the ability of topoisomerase I to cleave positively supercoiled DNA. Results confirm that the human enzyme maintains higher levels of cleavage with positively as opposed to negatively supercoiled substrates in the absence or presence of anticancer drugs. Enhanced drug efficacy on positively supercoiled DNA is due primarily to an increase in baseline levels of cleavage. Sites of topoisomerase I-mediated DNA cleavage do not appear to be affected by supercoil geometry. However, rates of ligation are slower with positively supercoiled substrates. Finally, intercalators enhance topoisomerase I-mediated cleavage of negatively supercoiled substrates but not positively supercoiled or linear DNA. We suggest that these compounds act by altering the perceived topological state of the double helix, making underwound DNA appear to be overwound to the enzyme, and propose that these compounds be referred to as ‘topological poisons of topoisomerase I’
Answer:
Appropriate Question:-
The output for a 60kg woman who runs up a 3m high flight of stairs in 3.5 sec.starting from rest but having a final speed of 2 m/s.
Given:-
Mass of woman=m=60kg.
Height=h=3m
Time=t=3.5secs.
To find :-
Here we want to calculate the output for a woman
Here first we should calculate work done first.
work \: done = mghworkdone=mgh
Applying the values,
work \: done = 10 \times 60 \times 3workdone=10×60×3
Work done= 1800Joule.
Now , lets calculate power,
power = \frac{workdone}{time \: taken} power=
timetaken
workdone
Now,
Applying the values ,
power = \frac{1800}{3.5} power=
3.5
1800
Power =514.2857 watt.
Hope it helps u mate .
Thank you .
