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3 years ago

If Jaliya has 5 paintings and paints 6 more how much does she have now?

Mathematics

2 answers:

gayaneshka [121]3 years ago

8 0

If ur learning addition then the answer is 11

5 + 6= 11

if ur learning multiplication the answer is 30

6 x 5 = 30

matrenka [14]3 years ago

4 0

Answer:

Step-by-step explanation:

5+6

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Determine formula of the nth term 2, 6, 12 20 30,42

nalin [4]

Check the forward differences of the sequence.

If $\{a_n\} = \{2,6,12,20,30,42,\ldots\}$ , then let $\{b_n\}$ be the sequence of first-order differences of $\{a_n\}$ . That is, for n ≥ 1,

$b_n = a_{n+1} - a_n$

so that $\{b_n\} = \{4, 6, 8, 10, 12, \ldots\}$ .

Let $\{c_n\}$ be the sequence of differences of $\{b_n\}$ ,

$c_n = b_{n+1} - b_n$

and we see that this is a constant sequence, $\{c_n\} = \{2, 2, 2, 2, \ldots\}$ . In other words, $\{b_n\}$ is an arithmetic sequence with common difference between terms of 2. That is,

$2 = b_{n+1} - b_n \implies b_{n+1} = b_n + 2$

and we can solve for $b_n$ in terms of $b_1=4$ :

$b_{n+1} = b_n + 2$

$b_{n+1} = (b_{n-1}+2) + 2 = b_{n-1} + 2\times2$

$b_{n+1} = (b_{n-2}+2) + 2\times2 = b_{n-2} + 3\times2$

and so on down to

$b_{n+1} = b_1 + 2n \implies b_{n+1} = 2n + 4 \implies b_n = 2(n-1)+4 = 2(n + 1)$

We solve for $a_n$ in the same way.

$2(n+1) = a_{n+1} - a_n \implies a_{n+1} = a_n + 2(n + 1)$

Then

$a_{n+1} = (a_{n-1} + 2n) + 2(n+1) \\ ~~~~~~~= a_{n-1} + 2 ((n+1) + n)$

$a_{n+1} = (a_{n-2} + 2(n-1)) + 2((n+1)+n) \\ ~~~~~~~ = a_{n-2} + 2 ((n+1) + n + (n-1))$

$a_{n+1} = (a_{n-3} + 2(n-2)) + 2((n+1)+n+(n-1)) \\ ~~~~~~~= a_{n-3} + 2 ((n+1) + n + (n-1) + (n-2))$

and so on down to

$a_{n+1} = a_1 + 2 \displaystyle \sum_{k=2}^{n+1} k = 2 + 2 \times \frac{n(n+3)}2$

$\implies a_{n+1} = n^2 + 3n + 2 \implies \boxed{a_n = n^2 + n}$

6 0

2 years ago

What is another way to write the absolute inequality |p|<12?

GaryK [48]

Answer:

$-12$

Step-by-step explanation:

$\left|p\right|$

The interval notation is (-12, 12).

$-12$

7 0

3 years ago

A club has 86 members, and there are 14 more girls than boys. how many boys and how many girls are members of the club?

Rus_ich [418]

X = boy count
x + 14 = girl count

x +x +14 = 86
2x + 14 = 86
2x = 72
x = 36
x + 14 = 50

There are 36 boys and 50 girls. Hope this helps!

6 0

3 years ago

What is the least common multiple of 60 and 90?

ivolga24 [154]

Answer:

180

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

The drama club is holding auditions for 5 different parts in a one-act play. If 9 people audition, how many ways can the roles b

erik [133]

Answer:

Step-by-step explanation:

I got it correct

6 0

3 years ago